Page 31 - Intro to Tensor Calculus
P. 31

27



               These cofactors are then combined into the single equation

                                                             1  ijk s t
                                                         i
                                                       A =    δ rst j k                               (1.1.25)
                                                                 a a
                                                         r
                                                            2!
                                             r
               which represents the cofactor of a . When the elements from any row (or column) are multiplied by their
                                             i
               corresponding cofactors, and the results summed, we obtain the value of the determinant. Whenever the
               elements from any row (or column) are multiplied by the cofactor elements from a different row (or column),
               and the results summed, we get zero. This can be illustrated by considering the summation
                                                    1  ijk  s t  m  1  ijk  m s t
                                            m
                                               i
                                                         a a a
                                           a A m  =  δ mst j k r  =  e  e mst a a a
                                            r
                                                                               j k
                                                                            r
                                                   2!             2!
                                                    1  ijk        1  ijk     i
                                                 =   e  e rjk |A| =  δ rjk |A| = δ |A|
                                                                             r
                                                   2!            2!
               Here we have used the e − δ identity to obtain
                                                                             i
                                                               i k
                                                                     i k
                                                                                 i
                                     δ  ijk  = e ijk e rjk = e jik e jrk = δ δ − δ δ =3δ − δ =2δ i
                                      rjk                      r k   k r     r   r    r
               which was used to simplify the above result.
                   As an exercise one can show that an alternate form of the above summation of elements by its cofactors
               is
                                                                   r
                                                         r
                                                        a A m  = |A|δ .
                                                         m  i      i
               EXAMPLE 1.1-26.        In N-dimensions the quantity δ j 1 j 2 ...j N  is called a generalized Kronecker delta. It
                                                                 k 1 k 2 ...k N
               can be defined in terms of permutation symbols as
                                                 e j 1 j 2 ...j N  e k 1 k 2 ...k N  = δ  j 1 j 2 ...j N  (1.1.26)
                                                                    k 1 k 2 ...k N
               Observe that
                                               δ j 1 j 2 ...j N  e k 1 k 2 ...k N  =(N!) e j 1 j 2 ...j N
                                                k 1 k 2 ...k N
               This follows because e k 1 k 2 ...k N  is skew-symmetric in all pairs of its superscripts. The left-hand side denotes
               a summation of N! terms. The first term in the summation has superscripts j 1 j 2 ...j N and all other terms
               have superscripts which are some permutation of this ordering with minus signs associated with those terms
               having an odd permutation. Because e j 1 j 2 ...j N  is completely skew-symmetric we find that all terms in the
               summation have the value +e j 1 j 2 ...j N . We thus obtain N! of these terms.
   26   27   28   29   30   31   32   33   34   35   36