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                        5.4 TREATMENT OF TURBULENT FLOWS



                             Figure 5.8. Wall function treatment.                  May 20, 2005  12:28 131
                                                                            P
                                                                                        Y p
                                                                            b

                                                                         ∆X 1


                          = u 1
                        For an impermeable wall, C s = 0 and, therefore, AS = µ eff  x 1 /y P . Also, the
                        no-slip condition requires that u 1b = 0atthe stationary wall. Thus

                                                ∂u 1      µ eff            µ eff
                                       τ w = µ eff     =      (u 1P − u 1b ) =  u 1P .     (5.92)
                                                ∂y         y P             y P
                                                    y=0
                        Now, replacing u 1P from Equation 5.86, we can show that

                                                 µ eff  τ w     ρκ u τ
                                                     =      =          ,                   (5.93)
                                                                    +
                                                  y P   u 1P  ln(Ey )
                                                                    P
                               +
                        where y = y P u τ /ν. Therefore, using Equation 5.90, we get
                               P
                                             ⎧  µ
                                                  ,                    y < 11.6,
                                                                        +
                                             ⎪
                                             ⎪
                                             ⎨  y P
                                       µ eff
                                           =            1/4  √                             (5.94)
                                                   ρκ C µ   e
                                        y P  ⎪               P          +
                                             ⎪             √      ,    y > 11.6.
                                                        1/4
                                             ⎩
                                                ln(Ey P C µ  e /ν)
                                                              P
                        Thus, for variable   = u 1 , for the near-wall node P, we may set
                                                                µ eff
                                    Su = Su + 0,     Sp = Sp +       x 1 ,   AS = 0.       (5.95)
                                                                 y P
                          = e
                        A further characteristic of the inner layer is that the shear stress through the layer
                        is constant and hence equals τ w . Also, experimental data demonstrate that in the
                        30 < y < 100 region, ∂e/∂y 
 0. Therefore, AS = 0. The implications of the
                               +
                        law of the wall thus can be absorbed through redefinition of S e for point P:
                                                     S e = G P − ρ   P ,                   (5.96)
                        where
                                                         2             2
                                                   ∂u 1           u 1P       ∂u 1
                                        G P 
 µ eff       = µ eff       = τ w              (5.97)
                                                    ∂y            y P        ∂y
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