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                            However, note that                  2D CONVECTION – COMPLEX DOMAINS
                                                                = x 2,b − x 2,a = β 1
                                                                                1
                                                x 2,E 2  =− x 2,P 2
                            and
                                                                                              (
                                                                              2

                                                                                  i               2
                                                                           2                     A .
                                                                           1    β (x i,E − x i,P )   c
                                                                                  1
                              x 2,a =− x 2,b = x 2,E 2  − x 2,P 2  = x 2,E 1  − x 2,P 1
                                                                       = β
                                                                             i=1

                               Making these substitutions in Equation 6.136 and carrying out the summation
                            indicated in Equation 6.135, and further separating out p x1,P  = p P , we obtain an
                            explicit equation for p x1,P  that reads as p x 1 ,P  = A/B, where
                                               NK )
                                           A =    
  β 1    2  (p E +  p E −  p P ) *#   V ck
                                                      1
                                               k=1
                                                  NK
                                                       1                       &

                                               −                    )(p b − p a )   V ck ,    (6.137)
                                                       1      − x 2,P 2
                                                      β (x 2,E 2
                                                  k=1
                            and
                                                           NK     2 #

                                                      B =      β 1 1     V ck ,               (6.138)
                                                          k=1
                            where p b and p a are evaluated using Equations 6.92 and 6.93. Similarly, we obtain
                            an equation for p x 2 ,P  = A/B, where
                                                NK )
                                                      2    2               *#

                                           A =       β    (p E +  p E −  p P )   V ck
                                                      1
                                               k=1
                                                  NK
                                                        2                      &

                                               −                    )(p b − p a )             (6.139)
                                                        1     − x 1,P 2           V ck
                                                      β (x 1,E 2
                                                  k=1
                            and
                                                           NK     2  #

                                                      B =      β 2 1      V ck .              (6.140)
                                                          k=1
                            6.3.12 Method of Solution
                            Our interest is in solving the set of equations (6.103) for all interior nodes P. Thus, if
                            there are NE elements, there are NE equations for each variable. Again, equations
                            for each variable are solved sequentially (see the next subsection). It has been noted
                            that the AP coefficients will dominate over the neighbouring coefficients AE k . But,
                            the positions of AE k in the coefficient matrix [A] will be arbitrary because of the
                            manner in which neighbouring nodes are numbered during grid generation using
                            ANSYS. This is unlike the case of structured grids (both Cartesian and curvilinear)
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