Page 268 - Introduction to Mineral Exploration
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10: EVALUATION TECHNIQUES  251


                 Sphalerite contains 67% zinc with a specific  Chalcopyrite contains 33% copper with a den-
                                 −3
                                                                           −3
                 gravity of 4.0 kg m .                        sity of 4.2 kg m .
                 (a) Fundamental variance of each sampling    (a) Fundamental variance of each sampling
                 stage (see also Box 10.1). Critical content  stage.
                   (a L ) = 7% zinc = 10.5% sphalerite as a fraction  Critical content (a L ) = 0.7% = 2.1% chalcopyrite
                 = 0.105.                                     as a fraction = 0.021.
                   Constitution factor (c):                     Constitution factor (c)

                                                                       0
                          − .105
                         1
                        (   0   )                                   1  −    .021
                       =         [(1  −    .105 ) .0  +   ( .105 ) . ]  =   [(1 − 0.105)4.0 + (0.105)2.7]
                                                     2
                                                      7
                                                0
                                     0
                                          4
                           . 0 105                                     . 0 021
                       = 8.52(3.58 + 0.28) = 32.89, say 33.       = 46.62(4.11 + 0.06) = 194.4, say 195.
                   Heterogeneity constant (C)                 Heterogeneity constant (C) = cβfg = 195 × 1 ×
                                                              0.5 × 0.25 = 24.38.
                        = cβfg = 33 × 1 × 0.5 × 0.5 = 4.13.     Fundamental variance:
                   Fundamental variance:                              C
                                                                                               −3
                                                                    =    = 24.38/125,000 = 195 × 10 .
                          C                                               K
                        =    = 24.38/125,000 = 33 × 10 −6
                              K                               (b) Total variance (TE) of the sampling scheme.
                                                              As above but, suppose, the system consists of
                 (b) Total variance (TE) of the sampling scheme.
                 At each reduction stage the total variance is  five reduction stages each ending on the safety
                 equal to double the fundamental variance. The  line. The total error variance now equals 10
                 complete sampling scheme consists of four    times (2 × 5) the fundamental variance.
                 reduction stages (Fig. 10.5a) each ending on the                               −6
                 safety line (see text). Consequently, the total  Total variance (TE) = 10 × (195 × 10 )
                                                                                             −6
                 variance equals eight times (2 × 4) the funda-                    = 1950 × 10
                 mental variance as calculated above.
                                                              Relative standard deviation = (1950 × 10 )  =
                                                                                                  −6 −2
                                                                    −3
                                             −6
                                                        −6
                 Total variance (TE) = 8 × (33 × 10 ) = 264 × 10 .  44 × 10  = 4.4%.
                                                              Absolute standard deviation as % of
                   Relative standard deviation =  (264 ×  10 − 6 )  mineral = 2.1% chalcopyrite × 4.4% = 0.09%
                                            = 16.2 × 10  −6   chalcopyrite.
                                                              Absolute standard deviation as % of metal =
                 Absolute standard deviation as % of mineral =  0.09% × 33% = 0.03% copper.
                 10.5% sphalerite × 1.6% = 0.17% sphalerite.  The confidence at 95% probability is ±2 SD =
                 Absolute standard deviation as % of metal =  ±2(0.03%) = 0.06% copper.
                 0.17% sphalerite × 67% = 0.11% zinc.         The two-sided confidence level is then 0.7% ±± ±± ±
                 The confidence level at 95% probability is ±2  0.06% copper at 95% probability, which is an
                 SD = ±2(0.11%) = 0.22% zinc.                 acceptable result. Generally a relative standard
                 The two-sided confidence level is then  7%    deviation of <5% is acceptable.
                 ± ± ± ± ± 0.22 zinc at 95% probability, which is an
                 acceptable result. Generally, a relative stand-  4 Calculation of the weight of a sample (M) to
                 ard deviation of <5% is acceptable.          be taken knowing the confidence interval.
                                                              (a) Introduction (see section 10.1.4)
                 3 Calculation of total variance (TE) and
                                                                                  3
                                                                                     2
                 double-sided confidence interval: chalcopyrite              M = Cd /S (FE)
                 mineralisation.
                 A prospect contains chalcopyrite mineralisa-  (b) Sphalerite mineralisation.
                 tion of grade 0.7% copper (X) in gangue of   Sphalerite mineralisation assays 7% zinc and
                                −3
                 density 2.7 kg m .                           the confidence level required is ± 0.2% zinc at
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