Page 329 - Machinery Component Maintenance
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&lancing  of  Machinery Components   31 1

                  Index-Balancing Procedure

                    A procedure of repetitively balancing and indexing (by 1 SO0) one com-
                  ponent against another leads to diminishing residual  unbalance  in both,
                  until eventually one component can be indexed against the other without
                  a significant change in residual unbalance. Index-balancing may be used
                  to eliminate the unbalance errors in an end-drive adapter, for biasing an
                  arbor or for improving the rcsidual  unbalance in  a rotor mounted on an
                  arbor.
                    If  the procedure  is used for a single-plane application  (e.g.,  an end-
                  drive adapter), one half of the residual unbalance (after the first index-
                  ing) is corrected in the adapter, the other half in the rotor. The cycle may
                  have to be repeated once or twice until a satisfactory residual unbalance
                  is reached.
                    Care should be taken that after each indexing step, set screws are tight-
                  ened with the same torque and in the same sequence. The procedure does
                  not work well unless the position of the indexed component is precisely
                  repeatable.


                    If  the above iterative process becomes too tedious, a graphic solution
                  may be used.  It is described below for a two-plane rotor mounted on an
                  arbor, with  Figure 6-38 showing a typical plot for one plane.

                    1.  Balance arbor by itself to minimum achievable residual unbalance.
                    2.  Mount rotor on arbor, observing prior cautionary notes concerning
                       keyways, set screws, and fits.
                    3. Take unbalance readings for both planes and plot points P on sepa-
                       rate graphs for each plane. (Only one plot for one plane is shown in
                       Figure 6-38. The reading for this, say the left plane, is assumed to
                       be 35 units at an angular position of 60".)
                    4. Index rotor on arbor by  180".
                    5.  Take unbalance readings for both planes and plot them as points P ' .
                       (Reading for left plane assumed to be 3 1 units at an angle of 225 O .)
                    6.  Find midpoint R on line connecting points P and P' .
                    7.  Draw  line SS' parallel to PP'  and passing through 0.
                    8.  Determine angle of OS  (52" for left plane) and distance RP (32.5
                       units for left plane). Add correction  mass of  32.5 units at 52" to
                       rotor  in left correction plane.
                    9.  Steps 6-8  must also be performed for the right plane. The rotor is
                       now balanced and the residual  unbalance  (OR in Figure 6-38) re-
                       maining in the arborhotor assembly is due to arbor unbalance and
                       run-out. If this residual unbalance is corrected by adding a correc-
                       tion mass to the arbor equal but  opposite to OR, the arbor is cor-
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