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ISOMORPHOUS REPLACEMENT   93

        spectrometry, gel electrophoresis, and microPIXE  degree of substitution for each heavy atom. An ideal
        (particle-induced X-ray emission). However, it is  case is one in which: (a) the native and derivative
        important to note that most of these techniques are  data are of very good quality, (b) the derivative
        just a guide that can help in evaluating derivative  shows a high degree of isomorphism, (c) only one
        formation, but the ultimate method is to identify  highly substituted heavy atom is present per macro-
        intensity changes between native and derivative  molecule, and (d) the heavy atom is of sufficiently
        crystals and to be able to confirm the significance of  high atomic number to give significant differences.
        these changes by calculating the position of ordered  A simple example of how to interpret a Patterson
        heavy-atomsites. Thiscanbeachievedbycomparing  map is described by Abdel-Meguid (1996).
        the different statistics calculated from the native and
        putative derivative data or between Friedel mates  6.7.2 Difference Fourier
        within the derivative data; significant differences
        should indicate successful derivative formation.  As can be seen from Eq. 4, a Fourier synthesis
                                                     requires phase angles as input, thus it cannot be
                                                     used to locate heavy-atom positions in a derivative
        6.7 Determination of heavy-atom
        positions                                    if no phase information exists. However, it can be
                                                     used to determine such positions in a derivative, if
        By far, the most common procedure for the deter-  phases are already available from one or more other
        mination of heavy-atom positions is the difference  derivatives. As in the case of a difference Patterson,
        Patterson method; it is often used in combination  the Fourier synthesis here also employs difference
        with the difference Fourier technique to locate sites  coefficients. They are of the form:
        in second and third derivatives.
                                                       m(F PH − F P )e iα P                (7)
                                                     where F PH and F P are the structure factor amplitude
        6.7.1 Difference Patterson
                                                     of the derivative and the native, respectively; α P the
        The Patterson function (Patterson, 1934) is a phase-  protein phase angle calculated from other deriva-
        less Fourier summation similar to that in Eq. 4 but  tives; and m (figure of merit; whose value is between
                  2
        employingF ascoefficients, thusitcanbecalculated  zero and one) is a weighting factor related to the
        directly from the experimentally measured ampli-  reliability of the phase angle.
        tudes (F P ) without the need to determine the phase  The success of this technique is highly depen-
                                              2
        angle. In the case of macromolecules, (F PH −F P ) are  dent on the correctness of α P , since it has been
        used as coefficients in Eq. 4 to produce a Patterson  clearly demonstrated that Fourier summations with
        map (hence the name difference Patterson). Such a  correct phases but wrong amplitudes can result in
        map contains peaks of vectors between atoms (inter-  the correct structure, while having incorrect phases
        atomic vectors). Thus in the case of a difference  even with correct amplitudes results in the wrong
        Patterson of macromolecules, it is a heavy-atom vec-  structure.
        tor map. For example if a structure has an atom  Difference Fourier techniques are most useful
        at position (0.25, 0.11, 0.32) and another atom at  in locating sites in a multisite derivative, when a
        position (0.10, 0.35, 0.15), there will be a peak in  Patterson map is too complicated to be interpretable.
        the Paterson map at position (0.25–0.10, 0.11–0.35,  The phases for such a Fourier must be calculated
        0.32–0.15), meaning a peak at (0.15, −0.24, 0.17).  from the heavy-atom model of other derivatives
          The interpretation of Patterson maps requires  in which a difference Patterson map was success-
        knowledge of crystallographic symmetry and space  fully interpreted, and should not be obtained from
        groups. Chapter 4 of Blundell and Johnson (1976)  the derivative being tested, in order not to bias
        offers a concise review of these topics. The ease of  the phases. Also, difference Fourier techniques can
        interpretation of these maps depends on the quality  be used to test the correctness of an already identi-
        of the data, the degree of isomorphism, the num-  fied heavy-atom site by removing that site from the
        ber of heavy-atom sites per macromolecule and the  phasing model and seeing whether it will appear in
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