Page 113 - Marks Calculation for Machine Design
P. 113

P1: Sanjay
                          January 4, 2005
                 Brown˙C02
        Brown.cls
                           M
                            M max     16:18      BEAMS                             95
                                               +        +
                                   a                                  a
                              0                                               x
                                                    L/2                  L
                         –(wa 2 )/2

                         FIGURE 2.77  Bending moment diagram.

                    and the maximum positive bending moment (M max@midpoint ) located at the midpoint of the
                    beam is given by Eq. (2.57),
                                                    wL 2
                                                              a
                                       M max@ midpoint =  1 − 4                 (2.57)
                                                     8        L
                      Note that the bending moment at the midpoint of the beam will be zero if the overhang
                    (a) is one-fourth the length of the beam (L), that is (a = L/4).



                              U.S. Customary                      SI/Metric
                    Example 2. Calculate the shear force (V ) and  Example 2. Calculate the shear force (V ) and
                    thebendingmoment(M)foradoubleoverhang-  bending moment (M) for a double overhanging
                    ing beam of length (L) and overhangs (a) with  beam of length (L) and overhangs (a) with a
                    a uniform distributed load (w), at a distance (x),  uniform distributed load (w), at a distance (x),
                    where                              where
                     w = 15 lb/ft                       F = 225 N/m
                      L = 12 ft, a = 2ft                L = 4m, a = 0.6 m
                      x = 4ft                            x = 1.2 m
                    solution                           solution
                    Step 1. Note that the distance (x) of4ftis  Step 1. Note that the distance (x) of 1.2 m is
                    between the supports,              between the supports,
                      a ≤ x ≤ L − a  or 2 ft ≤ 4ft ≤ 10 ft  a ≤ x ≤ L − a  or  0.6m ≤ 1.2m ≤ 3.4m
                    Step 2. As the distance (x) is between the  Step 2. As the distance (x) is between the
                    supports, determine the shear force (V ) from  supports, determine the shear force (V ) from
                    Eq. (2.53b)as                      Eq. (2.53b)as
                             w                                 w
                         V =   [L − 2 x]                   V =   [L − 2 x]
                             2                                 2
                             15 lb/ft                          225 N/m
                           =      [12 ft − 2 (4ft)]          =       [4 m − 2 (1.2m)]
                               2                                 2
                           = (7.5 lb/ft)(12 ft − 8ft)        = (112.5 N/m)(4m − 2.4m)
                           = (7.5 lb/ft)(4ft)                = (112.5 N/m)(1.6m)
                           = 30 lb                           = 180 N
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