Page 137 - Marks Calculation for Machine Design
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P1: Sanjay
                                      16:18
                          January 4, 2005
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                 Brown˙C02
                              U.S. Customary     BEAMS            SI/Metric       119
                    Step 4. As shown in Fig. 2.109, this maximum  Step 4. As shown in Fig. 2.109, this maximum
                    bending moment (M max ) of 625 ft · lb occurs at  bending moment (M max ) of 900 N · m occurs at
                    the right end of the beam, meaning at the wall  the right end of the beam, meaning at the wall
                    support.                           support.
                             w
                             A                                            B
                                               ∆
                                                   L
                             FIGURE 2.110  Beam deflection diagram.
                    Deflection. For this loading configuration, the deflection ( ) along the beam is shown in
                    Fig. 2.110, and given by Eq. (2.77) for values of the distance (x) from the left end of the
                    beam, as
                                        w    4    3     4
                                     =     (x − 4L x + 3L )  0 ≤ x ≤ L          (2.77)
                                       24 EI
                    where   = deflection of beam
                         w = uniform distributed load
                         x = distance from left end of beam
                         L = length of beam
                         E = modulus of elasticity of beam material
                         I = area moment of inertia of cross-sectional area about axis through centroid
                     The maximum deflection (  max ) occurs at the free end, and is given by Eq. (2.78),
                                                wL 4
                                            max =      at  x = 0                (2.78)
                                                8 EI
                              U.S. Customary                      SI/Metric
                    Example 4. Calculate the deflection ( ) for  Example 4. Calculate the deflection ( ) for
                    a cantilevered beam with a uniform distributed  a cantilevered beam with a uniform distributed
                    load (w) acting across its entire length (L),at  load (w) acting across its entire length (L), at
                    a distance (x) from the left end of the beam,  a distance (x) from the left end of the beam,
                    where                              where
                     w = 50 lb/ft                       w = 800 N/m
                      L = 5ft                           L = 1.5 m
                      x = 4ft                            x = 1.2 m
                                  2
                                                                 9
                              6
                                                                     2
                      E = 10 × 10 lb/in (aluminum)      E = 100 ×10 N/m (aluminum)
                      I = 36 in 4                        I = 1,500 cm 4
                    solution                           solution
                    Step 1. Calculate the stiffness (EI).  Step 1. Calculate the stiffness (EI).
                                          4
                                                                        2
                                 6
                                     2
                                                                     9
                                                                                4
                       EI = (10 × 10 lb/in )(36 in )      EI = (100 × 10 N/m )(1,500 cm )
                                          1ft 2                  1m 4
                                  8   2
                          = 3.60 × 10 lb · in ×              ×       4
                                         144 in 2              (100 cm)
                                 6
                                                                   6
                          = 2.5 × 10 lb · ft 2              = 1.5 × 10 N · m 2
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