Page 273 - Marks Calculation for Machine Design
P. 273

P1: Shibu
                                      14:56
                          January 4, 2005
                 Brown˙C06
        Brown.cls
                      Point 4:
                                                 −25
                                         1
                                            25
                               σ 1  σ 2 STATIC DESIGN AND COLUMN BUCKLING         255
                                 −    =   =    −
                              S ut  S uc  n  30   90
                              1    25  −25    25   25    75  25    100
                                =    −      =    +    =    +    =     = 1.11
                              n    30   90    30   90    90  90    90
                                   1
                              n =     = 0.90 (unsafe)
                                  1.11
                      Point 5:
                               σ 1  σ 2  1  15   −55
                                 −    =   =    −
                              S ut  S uc  n  30   90
                              1    15  −55    15   55    45  55    100
                                =    −      =    +    =    +    =     = 1.11
                              n    30   90    30   90    90  90    90
                                   1
                              n =     = 0.90 (unsafe)
                                  1.11
                    where the factors-of-safety found are less than one and indicates an unsafe static condition.
                    This is why the Coulomb-Mohr theory is more conservative, or more restrictive, in this
                    region of the diagram.
                                                 SI/Metric
                    Example 2. Plot the combinations given in the table below of the principal stresses (σ 1 , σ 2 )
                    on a static design coordinate system for brittle materials. Show the boundaries of the recom-
                    mended theories for determining if the combinations are safe, along with the four special
                    load lines shown in Fig. 6.15. Also, determine the factor-of-safety for each combination. Use
                    an ultimate strength in tension (S ut ) of 210 MPa and an ultimate strength in compression
                    (S uc ) of 630 MPa that are typical values for cast iron.
                                   Principal stresses (in MPa)
                                   Point  Principal stress (σ 1 )  Principal stress (σ 2 )
                                     1        280            −105
                                     2        210              0
                                     3        140             140
                                     4        175            −175
                                     5        105            −385

                    solution
                    Step 1. Plot the combinations of principal stresses from the given table.
                      This is shown in Fig. 6.17. Notice that the combination of principal stresses for point 1
                    falls outside the boundary in the fourth (IV) quadrant, the combination for point 2 falls
                    on the uniaxial load line directly on the boundary, the combination for point 3 falls on the
                    (σ 1 = σ 2 > 0) biaxial load line inside the boundary, the combination for point 4 falls on
                    the pure shear load line outside the boundary defined by the Coulomb-Mohr theory, but
                    inside the boundary defined by the maximum-normal-stress theory, and the combination
                    for point 5 falls outside the boundary defined by the Coulomb-Mohr theory, but inside the
                    boundary defined by the modified Coulomb-Mohr theory.
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