Page 42 - Marks Calculation for Machine Design
P. 42

P1: Shibu
                          January 4, 2005
                                      12:26
                 Brown˙C01
        Brown.cls
                  24
                                           STRENGTH OF MACHINES
                       BENDING
                  1.5
                  Figure 1.23 shows a simply-supported beam with a concentrated force (F) located at its
                  midpoint. This force produces both a bending moment distribution and a shear force distri-
                  bution in the beam. At any location along the length (L) of the beam, the bending moment
                  produces a normal stress (σ) and the shear force produces a shear stress (τ).
                                                   F
                                       L/2
                            A                                           B
                                                  L
                            FIGURE 1.23  Bending.
                    It is assumed that the bending moment and shear force is known. If not, bending moment
                  and shear force distributions, as well as deflection equations, are provided in Chap. 2 for
                  a variety of beam configurations and loadings. Note that beam deflections represent the
                  deformation caused by bending. Also, there is no explicit expression for strain owing to
                  bending, because again, there are so many possible variations in beam configuration and
                  loading.
                  Stress Owing to Bending Moment. Once the bending moment (M) has been determined
                  at a particular point along a beam, then the normal stress distribution (σ) can be determined
                  from Eq. (1.35) as
                                                   My
                                               σ =                             (1.35)
                                                    I
                  where (y) is distance from the neutral axis (centroid) to the point of interest and (I) is area
                  moment of inertia about an axis passing through the neutral axis.
                    The distribution given by Eq. (1.35) is linear as shown in Fig. 1.24, with the maximum
                  normal stress (σ max ) occurring at the top of the beam, the minimum normal stress (σ min )
                  occurring at the bottom of the beam, and zero at the neutral axis (y = 0).

                                                     s  max
                                                          y
                               M                           0         M


                                            s min
                               FIGURE 1.24  Bending stress distribution.
                    For the directions of the bending moments (M) shown in Fig. 1.24, which by standard
                  convention are considered negative, (σ max ) is a positive tensile stress and (σ min ) is a negative
                  compressive stress. Also, the term neutral axis gets its name from the fact that the bending
                  stress is zero, or neutral, when the distance (y) is zero.
                    Some references place a minus sign (−) in front of the term on the right hand side
                  of Eq. (1.35) so that when the bending moment (M) is positive, a compressive stress
   37   38   39   40   41   42   43   44   45   46   47