Page 451 - Marks Calculation for Machine Design
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P2: Sanjay
        P1: Shibu/Rakesh
                          January 4, 2005
                                      15:34
        Brown.cls
                 Brown˙C10
                              U.S. Customary  MACHINE MOTION      SI/Metric       433
                    Step 2. Substitute the velocity (v A ) found in  Step 2. Substitute the velocity (v A ) found in
                    step 1 and the given radius (r) of the rolling  step 1 and the given radius (r) of the rolling
                    wheel in Eq. (10.51) to determine the angular  wheel in Eq. (10.51) to determine the angular
                    velocity (ω) as                    velocity (ω) as
                            v A  88 ft/s                       v A  26.8 m/s
                        ω =   =                            ω =   =
                            rev  0.67 ft                      rev   0.2m
                               rad  1rev  60 s                   rad  1rev   60 s
                          = 132  ×      ×                   = 134   ×     ×
                               s   2π rad  1 min                  s   2πrad  1 min
                          = 1,260 rpm                       = 1,280 rpm
                      From the principles of relative motion, the velocity of any other point on the wheel will
                    be the velocity (v A ), which has a magnitude of (rω), plus an additional velocity equal to
                    (rω) except directed perpendicular to the line connecting the point with the center of the
                    wheel and is in the direction of the angular velocity (ω). Fig. 10.22 shows the velocities of
                    three special points B, C, and D, and why the velocity of point P is in fact zero.
                                                            v
                                                  B         B
                                           w
                                                         v A  rw
                                               v
                                         rw     C
                                                        r
                                                              D
                                                                  v A
                                         C    v A  A  v  = rw
                                                      A
                                                             rw   v D
                                              rw         v A
                                                            = 0
                                                          v P
                                 FIGURE 10.22  Velocity of special points on a rolling wheel.
                      Therefore, the velocity at the top of the wheel, point B, has a magnitude

                                        v B = v A + rω = v A + v A = 2 v A     (10.52)
                    which is twice the velocity of the center of the wheel (v A ) and directed to the right as shown.
                    Also, the velocity of the instantaneous contact point P is zero as the velocity (v A ) to the
                    right is canceled by the velocity (rω) to the left.
                      The velocity (v C ) at the left side of the wheel, point C, has a magnitude given by the
                    pythagorean theorem as
                                                                  √

                                           2     2       2     2
                                  v C =  (v A ) + (rω) =  (v A ) + (v A ) =  2 v A  (10.53)
                                      ◦
                    and directed upward at 45 relative to the horizontal as shown.
                      Similarly, the velocity (v D ) at the right side of the wheel, point D, has a magnitude given
                    by the pythagorean theorem as
                                                                  √

                                           2     2       2     2
                                  v D =  (v A ) + (rω) =  (v A ) + (v A ) =  2 v A  (10.54)
                                         ◦
                    and directed downward at 45 relative to the horizontal as shown.
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