Page 63 - Marks Calculation for Machine Design
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P1: Sanjay
                                      16:18
                          January 4, 2005
        Brown.cls
                 Brown˙C02
                              U.S. Customary     BEAMS            SI/Metric        45
                    Step 3. Calculate the maximum bending  Step 3. Calculate the maximum bending
                    moment (M max ) from Eq. (2.8) as  moment (M max ) from Eq. (2.8) as
                            Fab  (10,000 1b)(6ft)(2ft)         Fab  (45,000 N)(2m)(1m)
                      M max =  =                         M max =  =
                             L         8ft                     L          3m
                                  2
                            120,000 ft · lb                    90,000 N · m 2
                          =           = 15,000 ft · lb       =          = 30,000 N · m
                                8ft                               3m
                    Step 4. Figure 2.21, this maximum bending  Step 4. Figure 2.21, this maximum bending
                    moment (M max ) of 15,000 ft · lb occurs where  moment (M max ) of 30,000 N · m occurs where
                    the force (F) acts.                the force (F) acts.
                                                               F
                                               a                   b
                              A                       ∆                   B

                                                    L
                              FIGURE 2.22  Beam deflection diagram.


                    Deflection. For this loading configuration, the deflection ( ) along the beam is shown in
                    Fig. 2.22, and given by Eq. (2.9a) for values of the distance (x) from the left end of the
                    beam to where the force (F) acts, and given by Eq. (2.9b) for values of the distance (x)
                    from where the force (F) acts to the right end of the beam.
                                      Fbx   2   2   2
                                   =      (L − b − x )   0 ≤ x ≤ a              (2.9a)
                                      6 EIL
                                      Fa (L − x)     2   2
                                   =          (2 Lx − a − x )  a ≤ x ≤ L        (2.9b)
                                        6 EIL
                    where   = deflection of beam
                         F = applied force at an intermediate point
                         x = distance from left end of beam
                         L = length of beam
                         a = location of force (F) from left end of beam
                         b = location of force (F) from right end of beam
                         E = modulus of elasticity of beam material
                         I = area moment of inertia of the cross-sectional area about axis through centroid

                      Note that the deflection ( ) is downward for all values of the distance (x), and that the
                    distance (x) in Eq. (2.9a) must be between 0 and the distance (a), and the distance (x) in
                    Eq. (2.9b) must be between the distance (a) and the length of the beam (L). The deflection
                    will not be symmetrical about the location of the force (F), and as will be seen shortly, the
                    maximum deflection does not occur where the force acts.
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