Page 93 - Marks Calculation for Machine Design
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P1: Sanjay
                                      16:18
                          January 4, 2005
        Brown.cls
                 Brown˙C02
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                                                 BEAMS
                      The bending moment distribution is given by Eq. (2.36a) for the values of the distance
                    (x) from the left end of the beam to the roller, and Eq. (2.36b) from the roller to the free
                    end. (Always measure the distance (x) from the left end of any beam.)
                                           Fa
                                     M =−    x    0 ≤ x ≤ L                    (2.36a)
                                           L
                                     M =−F(L + a − x)   L ≤ x ≤ L + a          (2.36b)
                      The bending moment (M) distribution is shown in Fig. 2.56.
                          M
                                                                       L + a
                             0                                               x
                                                L                  a
                                                      −          −
                            –Fa

                          FIGURE 2.56  Bending moment diagram.


                      Note that the bending moment (M) is zero at the left end, decreases linearly to a maximum
                    negative value at the roller, and then increases linearly back to zero. The maximum bending
                    moment (M max ), the absolute value of this negative quantity, occurs at the roller and is
                    given by Eq. (2.37).
                                                M max = Fa                      (2.37)



                              U.S. Customary                      SI/Metric
                    Example 2. Calculate the shear force (V ) and  Example 2. Calculate the shear force (V ) and
                    bending moment (M) for a single overhanging  bending moment (M) for a single overhanging
                    beam of length (L) and overhang (a) with a  beam of length (L) and overhang (a) with a
                    concentrated force (F) acting at the free end, at  concentrated force (F) acting at the free end, at
                    a distance (x), where              a distance (x), where
                      F = 450 lb                        F = 2,000 N
                      L = 3 ft, a = 1ft                 L = 1m, a = 0.3 m
                      x = 2ft                            x = 0.6 m
                    solution                           solution
                    Step 1. Determine the shear force (V ) from  Step 1. Determine the shear force (V ) from
                    Fig. (2.55) as                     Fig. 2.55 as
                              Fa    (450 lb)(1ft)               Fa   (2,000 N)(0.3m)
                         V =−    =−                        V =−    =
                               L       3ft                       L       1m
                              450 ft · lb                       600 N · m
                           =−        =−150 lb                =−        =−600 N
                                3ft                               1m
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