Page 144 - Mathematical Models and Algorithms for Power System Optimization
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Load Optimization for Power Network 135
















                                                     Fig. 5.2

                                            5-Bus test system for state 1.






               (2) Based on basic data and topology of the network, find the bus branch incidence matrix R,
                    branch admittance diagonal matrix B b , bus admittance matrix B, and bus admittance
                                              0
                    dimension reduction matrix B , respectively.
                                                 2                 3
                                                    11      00 0
                                                   0    110 0
                                                 6                 7
                                                 6                 7
                                             R ¼  10        10 0   7
                                                 6
                                                 6                 7
                                                 4 0    101 0      5
                                                   0    0  10 1
                      2                              3   2                                    3
                        1=x 12  0     0     0     0        30:675    0      0      0       0
                          0           0     0     0          0    31:153    0      0       0
                      6       1=x 23                 7   6                                    7
                      6                              7   6                                    7
                 B b ¼  6  0    0   1=x 13  0     0  7  ¼  6  0      0   30:675    0       0  7
                      6                              7   6                                    7
                      4   0     0     0   1=x 24  0  5   4   0       0      0    13:605    0  5
                          0     0     0     0   1=x 35       0       0      0      0    21:413
                                   2                                             3
                                     61:350  30:675  30:675        0        0
                                      30:675 75:433  31:153  13:605         0
                                   6                                             7
                                   6                                             7
                               B ¼  30:675  31:153 83:241          0      21:413  7
                                   6
                                   6                                             7
                                   4    0      13:605     0      13:605     0    5
                                        0        0        0      21:413 21:413
                                        2                                   3
                                          61:350  30:675  30:675        0
                                          30:675 75:433  31:153  13:605
                                        6                                   7
                                     0
                                   B ¼  6                                   7
                                        4   30:675  31:153 83:241       0   5
                                             0     13:605      0     13:605
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