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5.6 Unitary and Orthogonal Matrices                                                329
                                                      z                               z




                                                                                             v
                                                                                             π/4
                                           π/2
                                                                     y                               y
                                     x              View (a)    v    x             View (b)
                                                         z
                                                                                        z

                                                             π/3





                                                                        y
                                                              v                                        y
                                     x                                 x
                                                                                                   v
                                                      View (c)                        View (d)
                                                                  Figure 5.6.5
                                    Problem: If the coordinates of each vertex in View (a) are specified, what are
                                    the coordinates of each vertex in View (d)?
                                    Solution: If P x is the rotator that maps points in View (a) to corresponding
                                    points in View (b), and if P y and P z are the respective rotators carrying View
                                    (b) to View (c) and View (c) to View (d), then
                                                                                               √
                                                                                                  
                                           10      0         1     1  √ 0  1           √ 1/2  − 3/2   0
                                    P x =    00  −1 , P y = √    0    20 , P z =     3/2      1/2  0 ,
                                                                                                       
                                                    
                                                                            
                                                              2
                                           01      0              −1    0  1             0       0    1
                                    so
                                                                                   √ 
                                                                           1   1      6
                                                                    1    √    √     √
                                                    P = P z P y P x = √   3   3  − 2            (5.6.15)
                                                                   2 2
                                                                         −2    2      0
                                    is the orthogonal matrix that maps points in View (a) to their corresponding
                                    images in View (d). For example, focus on the vertex labeled v in View (a), and
                                    let v a , v b , v c , and v d denote its respective coordinates in Views (a), (b), (c),
                                                            T                            T
                                    and (d). If v a =( 110 ) , then v b = P x v a =( 101 ) ,
                                                                                                 √
                                                         √                                           
                                                            2                                       2/2
                                                                                                  √
                                    v c = P y v b = P y P x v a =   0   ,  and  v d = P z v c = P z P y P x v a =   6/2 .
                                                                                                       
                                                           0                                        0
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