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                                          Microbridges: Lumped-Parameter Modeling and Design

                              176   Chapter Four
                                  3           2           1


                                       l/2

                                               l

                              Figure 4.7  Full-length microbridge for torsional resonant frequency calculation.

                                The lumped-parameter stiffness (the ratio of the torsion moment
                              applied at the midspan – point 2 – to the resulting angular deforma-
                              tion) is
                                                             4GI t
                                                        k t,e  =  l                      (4.28)

                              and this is twice the stiffness of the half-length microbridge [Eq. (4.24)],
                              as expected.
                                The distribution function, which is needed to determine the lumped-
                              parameter mechanical moment of inertia corresponding to point 2 in
                              Fig. 4.7, and which is dynamically equivalent to the distributed mass
                              of the full-length microbridge undergoing free torsional vibrations, is
                              found by applying the method of unknown coefficients which has been
                              presented for bending vibrations. The torsional angle at a generic point
                              of abscissa x is sought of the following polynomial form:

                                                    ș (x) = a + bx + cx 2                (4.29)
                                                     x
                              The three unknown coefficients in Eq. (4.29) are determined by using
                              the following boundary conditions:
                                                                   l
                                              ș (0) = ș (l) =0  ș x( )  = ș x            (4.30)
                                                      x
                                               x
                                                                   2
                              As a result, the distribution function can be expressed as
                                                       ș (x)   4x(l í x)
                                                 f (x) =  x  =     2                     (4.31)
                                                  t
                                                         ș
                                                          x       l
                              It can be seen that this function satisfies the expected conditions:

                                                      0    x =0 and x = l
                                              f (x) =          l                         (4.32)
                                               t
                                                     { 1   x =
                                                              2





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