Page 325 - Mechanical design of microresonators _ modeling and applications
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                                         Microcantilever and Microbridge Systems for Mass Detection

                              324   Chapter Six
                                                     96(EI )
                                                          y 1
                                               k b,0  =                                  (6.65)
                                                        l  3
                              The stiffness after mass deposition becomes

                                             96(EI ) (EI ) [ l (EI ) + (l – l )(EI )
                                                           p
                                                  y
                                                                       p
                                                               y
                                                       y e
                                                                           y e
                                k =                1            1                        (6.66)
                                 b         4           2       2
                                     (EI ) 2 l +2l (l – l )(2l – ll + l )(EI ) (EI ) + (l – l ) 4 (EI ) 2
                                        y  1  p  p  p      p  p    y  1  y e   p    y e
                              The effective mass of the original half-length microbridge was given in
                              Eqs. (4.54) as
                                                      13
                                               m    =   m                                (6.67)
                                                 b,0  70  1
                              where  m 1   is the total mass of the substrate. The modified mass is
                              expressed based on Eq. (4.52) as
                                                   13
                                              m =     (m + f ǻm)                         (6.68)
                                                b  70   1    p
                              with f p  being defined in Eq. (4.53).
                                The bending resonant frequency ratio can now be formulated by using
                              Eqs. (6.65) through (6.68) in the form:

                                                                     2 4
                                                                (EI ) l +2l (l í l )(2l 2
                                                                    y 1 p  p     p
                                                                       2
                                                                íll + l (EI ) (EI )
                                                                        )
                                                                   p   p    y 1   y e      (6.69)
                                                                        4
                                Ȧ            m + f ǻ m          +(l í l )(EI ) 2
                                                                      p
                                                                            y e
                                  b,0  =0.277  1   p     ×
                                 Ȧ                m          3
                                  b                1        l (EI ) l (EI ) + (l í l )(EI )
                                                                 y  e  p  y 1     p    y e
                              By using the nondimensional parameters
                                        ǻm         t p       l p       E p        ȡ p
                                   f  =        c =      c =       c =        c =         (6.70)
                                    m   m 1    t   t 1   l   l     E   E 1    ȡ   ȡ 1
                              Eq. (6.69) becomes
                                                                     3
                                  Ȧ                                 c (1+ c c )
                                   b,0  = 0.784 1+ f f  (1 í c ) +   l    E t     +A
                                                              3
                                  Ȧ b              p m      l     1+ c c {4+ c 6
                                                                      E t     t          (6.71)
                                                                  +c (4+ c c ) }
                                                                    t    E t




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