Page 151 - Modeling of Chemical Kinetics and Reactor Design
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Reaction Rate Expression  121

                                Equation 3-39 shows that in the first order reactions, the half-life
                              is independent of the concentration of the reactant. This basis can be
                              used to test whether a reaction obeys first order kinetics by measur-
                              ing half-lives of the reaction at various initial concentrations of
                              the reactant.



                                              SECOND ORDER REACTIONS

                                A second order reaction occurs when two reactants A and B interact
                              in such a way that the rate of reaction is proportional to the first power
                              of the product of their concentrations. Another type of a second order
                              reaction includes systems involving a single reactant. The rate at any
                              instant is proportional to the square of the concentration of a single
                              reacting species.

                              Case 1

                                                            k
                                Consider the reaction  A B+ →  products. The rate equation for a
                              constant volume batch system (i.e., constant density) is:


                                 − ( r A ) =  −dC A  =  −dC B  = kC C B                  (3-40)
                                                          A
                                          dt     dt
                                The amount of A and B that have reacted at any time t can be
                              described by the following mechanism and set of equations.
                                From stoichiometry:
                                                                      A                  B

                              Amount at time t = 0                   C AO               C BO
                              Amount at time t = t                   C A                 C B
                              Amounts that have reacted            C   – C            C   – C
                                                                    AO   A             BO    B

                                C  = C    – (C    – C )                                  (3-41)
                                  B    BO      AO    A
                                Substituting Equation 3-41 into Equation 3-40, rearranging and
                              integrating between the limits gives

                                 C A        −dC                t
                                                               ∫
                                  ∫             A       )]  = kdt                        (3-42)
                                       [
                                    CC   BO  − (C AO  − C A
                                      A
                                 C AO                          0
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