Page 216 - Modeling of Chemical Kinetics and Reactor Design

186 Modeling of Chemical Kinetics and Reactor Design

Equation 3-273 is of the form Y = Ae BX and plotting ln{[C BO /(C AO
– 3X )]/1 – X } against t gives the slope B = k(C BO – 3C AO ).
A
A
Table 3-10 gives the values of ln{[C BO /(C AO – 3X )]/1 – X } and
A
A
t. The computer program PROG1 calculates the slope B from the
equation Y = Ae BX . From the slope, it is possible to determine the
rate constant k.
The constants for the equation are:

• A = 5.325
• B = 0.0056969
• Correlation Coefficient = 0.99984

The slope = k(C BO – 3C AO ) = 0.0057

.
C = 0 02864, C =0 1531
.
AO BO
. (
−
k 0 1531 3 0 02864) = 0 0057
.
•
.
0 06718k = 0 0057
.
.
m 3
k =0 0848
.
kmol ksec

m 3 l 1 kmol
= 0 0848 × 10 3 ×
.
3
k
kmol − sec m 3 10 mol
.
= 0 0848 l × 3 600 sec
,
10 3 sec• mol hr

l
= 0 305
.
mol − hr
Dillon obtained a value for the rate constant k = 0.300 1/(mol –
hr). Figure 3-21 shows a plot of ln{[C /(C AO – 3X )]/1 – X } against
A
A
BO
time t, where Y = ln{[C BO /(C AO – 3X )]/1 – X }.
A
A