Page 213 - Modeling of Chemical Kinetics and Reactor Design
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Reaction Rate Expression  183

                              Solution

                                The reaction in stoichiometry can be represented as

                                          
                                           k
                                 A + 3 B  → Products                                   (3-255)
                                Assuming that the reaction is second order in a constant volume
                              batch system, the rate equation is


                                 − ( r A ) =  −dC A  = kC C B                           (3-256)
                                                  A
                                          dt
                                From stoichiometry:

                                                                     A                   B
                              Amount at t = 0                       C AO                C  BO
                              Amount at t = t                       C A                  C B
                              Amounts that have reacted          (C AO  – C )        (C BO  – C )
                                                                        A
                                                                                             B
                              and (C     – C ) = 3(C     – C ).  The fractional conversion X  is
                                     BO     B       AO     A                               A
                              defined as

                                 X =  C AO  − C A                                       (3-257)
                                  A
                                        C AO
                              Therefore,

                                C  = C    (1 – X )                                      (3-258)
                                  A    AO       A
                                Differentiating Equation 3-258 with respect to time t gives


                                 −  dC A  = C AO  dX A                                  (3-259)
                                     dt         dt

                                The concentration of B is

                                 C =  C BO  −  C ( 3  AO  − C )                         (3-260)
                                  B
                                                    A
                                In terms of the fractional conversion, the concentration of B is

                                 C =  C  −3 C   X                                       (3-261)
                                  B    BO     AO  A
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