Page 138 - Modern Control Systems
P. 138

112              Chapter 2  Mathematical  Models of  Systems

                                                                 R
                                                         -
                                               o    W V        •AAAr      +
                                                    I lis)  >   I 2(s)
                                               VAs)      V ?<R      C


                                                             (a)







                            v,Q    ••
                                        L,  =  -GR  =  - 1
                                                        -
                                                    L,  = G/?=  - 1
                                                             (b)




                                                                  O—
                             VAs)                                                           V^s)
           FIGURE 2.49
           (a) Ladder network,
           (b) its signal-flow
           graph, and (c) its
           block diagram.                                    (c)



                            where  G  =  1/R, Z(s)  =  l/Cs,  and  ^(s)  =  I x  (we  omit  the  (5)). The  signal-flow
                            graph constructed  for  the four  equations is shown in Figure 2.49(b), and the corre-
                            sponding  block  diagram  is  shown  in  Figure  2.49(c).  The  three  loops  are
                                                         -
                               =  -GR  = 1 ,   =  -GR  = 1 ,       =  -GZ.  All loops touch the  forward
                                         -
                            L t             L 2             and L 3
                            path. Loops Li  and L 3 are nontouching. Therefore, the transfer  function  is
                                                                                  GZ
                                       T(s)  =
                                                   1  -  (Lj  +  L 2  +  L 3)  +  L rL 3  3  +  2GZ
                                                        1    =    1/&RC)
                                                    3RCs  + 2  s  +  2/(3RC)'

                            If one prefers to utilize block diagram reduction techniques, one can start at the out-
                            put with
                                                         V 3(s)  =  ZI 2(s).
                            But the block diagram shows that
                                                     I 2(s)  = G(V 2(s)  -  V 3(s)).
                            Therefore,
                                                   V 2(s)  = ZGV 2(s)  -  ZGV 3(s)
   133   134   135   136   137   138   139   140   141   142   143