Page 391 - Numerical Methods for Chemical Engineering
P. 391

380     8 Bayesian statistics and parameter estimation



                   The data of Table 8.2 yield the design matrix and response vector
                                                                       
                                       1 −1.0000  −1.0000          −4.6096
                                       1 −0.6990  −1.0000              
                                      
                                                         
                                                                  −4.3157 
                                       1 −1.0000                       
                                      
                                                                                      (8.31)
                                                  −0.6990 
                                                                  −4.2999 
                                       1 −0.6990  −0.6990   y =        
                                                         
                                  X = 
                                                                  −3.9988 
                                      
                                       1 −1.3010                       
                                                  −0.6990        −4.6224 
                                       1 −0.6990 −1.3010           −4.5818
                   The vector of parameters that we fit is
                                             θ = [log k 1  ν a  ν b ] T               (8.32)
                                                    10
                               T
                   We compute X X, and solve the linear system (8.23) to obtain
                                                                
                                                log k 1     −2.6032
                                                  10
                                        θ LS =    ν a    =    1.0224              (8.33)
                                                             0.9799
                                                  ν b
                   The estimated rate law for A + B → C from those data is then
                                              v a
                                      r R1 = k 1 C C  v b  = (0.0025)C 1.0224 C 0.9799  (8.34)
                                              A  B           A     B
                   For an elementary reaction, we expect ν a = ν b = 1, and our fitted values are indeed close
                   to 1. But, is the discrepancy from ν a = ν b = 1 due solely to measurement error? To answer
                   this question we need tools for testing hypotheses.
                   Example. Comparing protein expression data for two bacterial strains
                   Let us say that we have performed experiments to measure the protein expression rates of
                   wild-type and mutant cell strains.
                                    wild-type             mutant
                                                              
                                             sample       120.7   sample
                                    121.9 
                                                              
                                    113.4                119.5  
                                           subset mean           subset mean          (8.35)
                                          = 113.41             = 120.16
                                    112.2                116.5 
                                         
                                                               
                                    106.1                 124.0
                   Is the difference between strains significant in a statistical sense or just an artifact of mea-
                   surement noise?
                     To answer this question, we fit the data to the linear model
                                                y = θ 1 + θ 2 x + ε                   (8.36)
                   with the predictor variable

                                                   0,  wild-type
                                              x =                                     (8.37)
                                                   1,  mutant
                   If we estimate probable bounds for the value of θ 2 ,

                                                                                      (8.38)
                                                θ 2,lo ≤ θ 2 ≤ θ 2,hi
   386   387   388   389   390   391   392   393   394   395   396