Page 269 - Offshore Electrical Engineering Manual
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256    CHAPTER 7  Protection and Discrimination




                            The largest fuse on the accommodation switchboard is 400 A (fuse U). The
                         relay must discriminate with fuse U and permit the maximum load current of 547 A
                         to flow.
                            For discrimination with the fuse, the primary current setting should be approxi-
                         mately 3 times the fuse rating, i.e., 3 × 400 = 1200 A. Therefore the nearest relay set-
                         ting is 0.75 × 1500 = 1125 A (0.75 PSM).
                            The maximum fault level for fuse grading is 56.009 kA (from computer science
                         study). Therefore from the manufacturer’s fuse characteristics, the fuse operating
                         time t at 56 kA is 0.01 s. From the GEC Guide, the minimum relay operating time is
                         given by:
                                                 t + 0.4t + 0.15 = 0.164s

                            If the fault current from computer studies is 51.44 kA, then the fault current as a
                         multiple of the plug setting is 51,440/1125 = 46. The relay operating time at 46 times
                         the plug setting with a time multiplier setting (TMS) of 1 is 0.255 s, from the relay
                         characteristic. Therefore the required TMS is 0.164/0.255 = 0.64 ≈ 0.7.


                         RELAY T: RANGE 10%–200%, CT RATIO 1500/1
                         As the maximum loading of the accommodation switchboard is the same, the exer-
                         cise is similar to that for relay F but using the fault currents that the computer has
                         calculated for feeder T.
                            With the given fault current of 44,280 A, the equivalent relay PSM is
                         44,280/1125 = 39.4.  Therefore from the relay characteristic, using a PSM
                         of 39.4 and a  TMS of 1, the operating time is 0.255 s.  The required  TMS is
                         0.164/0.255 = 0.64 ≈ 0.7.

                         RELAY G: RANGE 10%–200%, CT RATIO 2000/1

                         In mode 1, the utilities switchboard would be feeding the emergency switchboard,
                         as the emergency generator would not be running. From the load flow data for the
                         emergency switchboard:
                                    Load = 455 kW + jl93 kVA r ≈ 649 A at 0.92 power factor
                                        Largest motor load ≈ 84 A at 0.8 power factor
                                      Motor starting current ≈ 504 A at 0.2 power factor
                            Therefore the maximum load during the starting of this motor is:
                                              Load − motor FLC + motor start


                         (597 + j253) − (67.2 + j50.4) + (100.8 + j494) = 939.6Aat0.67 power factor ≈ 1000 A
                            Relay G must permit the maximum load without tripping and must also coor-
                         dinate with the largest outgoing fuse on the emergency switchboard, i.e., fuse Cl
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