Page 250 - Op Amps Design, Applications, and Troubleshooting
P. 250

232    ACTIVE FILTERS


               value, we will have to select a different value for Q and C 2 and recompute the
               resistance values. Because of the wide range of resistance values typically required
               in a given design, it is not uncommon to have resistance values ranging from 1000
               ohms or less to well into the megohm ranges. Nevertheless, it should remain a
               goal to keep the resistance values above 1 kilohm and below 1 megohm if practi-
               cal. The lower limit is established by the output drive of the op amp and the effects
               on input impedance. The upper limit is established by the op amp bias currents
               and circuit sensitivity. That is, if the resistance values are very large, then the volt-
               age drops due to op amp bias currents become more significant. Additionally, if
               the resistances in the circuit are excessively high, then the circuit is far more prone
               to interference from outside noise, nearby circuit noise, or even unwanted cou-
               pling from one part of the filter to another. For our initial selection, let us choose to
               use 0.001-microfarad capacitors for Q and C 2.

               Compute the Value of Jt|. The value of resistor ^ is computed with Equa-
               tion (5.18).








               In the case of the present design, we compute the value for RI as






               We will plan to use a standard value of 200 kilohms. It should be noted, however,
               that the component values in an active filter are generally more critical than in
               many other types of circuits, so if close adherence to the original design goals is
               required, use either variable resistors for trimming or fixed resistors in a series
               and/or parallel combination, or use precision resistors.

               Compute the Value for R 2. Resistor K 2 is calculated with Equation (5.19).







                                                  a
               For our present design, we compute R 2 § follows:






               Compute the Value for & 3. Resistor R 3 is computed by simply doubling the
               value of RI. That is,
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