Page 302 - Petrophysics 2E
P. 302

LAB-DERIVED EVALUATION OF SHALY             273


                                                        TABLE 4.1 1
                                              f.AB0RATORY VALUES OF s,   AND IRL



                                             0.2                        46.1
                                             0.3                         17.6
                                             0.4                         8.9
                                             0.5                         5.2
                                             0.6                         3.4
                                             0.7                         2.3
                                             0.8                         1.7
                                             1 .o                         1  .0





                           the Shannon sandstone  [32]. The following approach is based on this
                           procedure.

                           (1) The effective volume concentration  of  clay-exchange cations, Qv ,
                               can be calculated from:






                               and the formation resistivity factor for the shaly sands is obtained
                               from the Waxman and Smits Equation 4.130, or:




                               where  the  formation water  resistivity  is  equal  to  0.386  ohm-m,
                               and the specific counterion activity or equivalent conductance of
                               clay-exchange cations is 2.9 liter/eq.ohm-m from Figure 4.40. Using
                               Equation 4.139 one obtains:


                               C,,  = (1 - 0.83e-0.5/0.386) 3.83 = 2.96

                               Inasmuch as RwCeq = 0.386 x  296 = 1.14, the equation describing
                               F* for the Shannon sandstone field is:

                               F*  = FR(~ + 1.144,)

                               The values of Qv and F * for the first core sample in Table 4.12 are:

                                                )
                                               1  (2.65) (0.042) = 0.30liter/eq.ohm-m
                               Qv=(&-
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