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276    PETROPHYSICS: RESERVOIR ROCK PROPERTIES



                                                 TABLE 4.13
                                    SUMMARY CALCUlATlONS OF IR, N*, AND  1;





                    0.2           46.10                  2.99                103.00
                    0.3           17.56                 2.94                  32.00
                    0.4            8.85                  2.91                 14.00
                    0.5            5.21                  2.88                  7.36
                    0.6            3.37                  2.86                  4.35
                    0.7            2.34                 2.84                   2.80
                    0.8            1.70                  2.82                  1.90
                    0.9            1.28                  2.77                  1.35



                            equal to 2.38. Thus, the equation of this straight line is:







                        (c)  Using this equation calculate the new IR values for selected S,
                            values and tabulate (Table 4.13).
                        (d)  Calculate the water saturation coefficient n* from Equation 4.137
                            for the same S, values as in Step (c):



                                                                                (4.143)



                            From Table 4.12, the arithmetic average value of Qv of the seven
                            samples is 0.63 meq/ml.  Hence RwCeqQv = 0.386 x  2.96 x
                            0.63  = 0.72, and  Equation 4.143 for the  Shannon sandstone
                            becomes:


                            n*= (&)In(
                                             IR (1 + 0.72/S,)

                            For Sw  = 0.4, for instance, the corresponding resistivity index
                            IR from Table 4.11 is 8.85, thus:

                            ".=(-)In( 1               1.71
                                   1110.40     8.85 (1 + 0.72/0.40)   = 2.91
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