Page 124 - Phase-Locked Loops Design, Simulation, and Applications
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MIXED-SIGNAL PLL ANALYSIS   Ronald E. Best                                              80
















































                      Figure 3.18 The waveforms shown demonstrate the pull-in process of a PLL which uses the
                              PFD. The frequency  ω   of the input signal  u   is assumed to be higher than the
                                                   1
                                                                        1
                              (scaled-down) frequency ω ′ of the VCO output signal. Consequently, u  toggles
                                                                                                d
                                                      2
                              between the states 0 and 1 (third trace). The average u  signal has the same effect as
                                                                              d
                              an equivalent signal u  with a constant duty cycle of 50 percent, as explained in
                                                  eq
                              the text. This greatly facilitates the computation of the averaged loop filter output
                              signal u  (see the bottom trace).
                                     f
             Obviously, the average duty cycle of u  is 50 percent. As Fig. 2.15 shows, the average duty
                                                   d
             cycle  δ varies very little with the ratio  ω /ω ′ and can be considered constant for this
                                                       1
                                                           2
             analysis. Because the time constant τ  of the loop filter is much larger than the period of the u
                                                1                                                      1
             signal in Fig. 3.18, an equivalent signal u  (having a constant duty cycle of 50 percent) would
                                                    eq
             have the same effect on the loop filter (this equivalent signal is also represented in Fig. 3.18).
             If the equivalent signal u  had a duty cycle of 100 percent, capacitor C  of the loop filter
                                      eq                                             1
             would simply charge toward the supply voltage U  with time constant τ  + τ  = (R  + R ) C ,
                                                                                             1
                                                                                                  2
                                                                                                      1
                                                                                       2
                                                             B
                                                                                  1
             because  C  is charged through the series connection  of resistors  R  and  R  (compare  Fig.
                       1                                                        1       2
             2.17a for symbol definitions). Because the duty cycle is only 50  percent, however, the
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