Page 248 - Physical Principles of Sedimentary Basin Analysis
P. 248

230                             Subsidence

                     1000                                2000

                     800
                                                         1500
                   subsidence [m]   600                 subsidence [m]   1000


                     400

                                                          500
                     200

                       0                                    0
                       0.0  0.2   0.4  0.6  0.8  1.0         0    10   20   30   40   50
                                            3
                             heat production [μW/m ]               crust thickness [km]
                 Figure 7.21. (a) The subsidence corresponding to radioactive heat production. (b) The subsidence as
                 a function of the thickness of the heat-producing crust. See Exercise 7.23 for the details.

                 (b) Insert the expression (6.61)for T m into z 1 and then z 1 into the integral (7.124), and
                 show that it can be written
                                  2
                               S 0 z m  1   1     S 0 z m  λ m    1 λ m         1
                        Tdz =            −     1 +           z m +    (T a − T 0 ) + z a .
                                λ c    12   4      2q m  λ c      4 q m         4
                                                                                   (7.126)
                 Figure 7.21a shows the subsidence as a function of heat production S 0 and Figure 7.21b
                 shows the subsidence as a function of the thickness of the crust z m . The other parameters
                                         ◦
                           ◦
                 are T 0 = 0 C, T a = 1300 C, z a = 120 km, z m = 35 km, S 0 = 1 μWm −3 , q m =
                 20 mW m −2 , λ c = 2.5W m −1  K −1 , λ m = 3W m −1  K −1 ,   c = 3300 kg m −3 ,   m =
                 2800 kg m −3  and α = 3 · 10 −5  K −1 .
                 (c) The thickness of the crust is reduced during lithospheric extension. How much extra
                 subsidence could one expect when a z m = 35 km thick crust is stretched and thinned with
                 β = 2?
                 Comments: The geotherm used in this exercise has the mantle heat flow q m as a bound-
                 ary condition at the base of the lithosphere. The alternative geotherm (6.65)–(6.66), where
                 the asthenosphere temperature T a is the boundary condition at the base of the lithosphere,
                 gives less temperature difference between the geotherms for non-zero and zero heat gen-
                 eration. Another point is that the loss in heat production from a thinned crust may be
                 counterbalanced by infill of a basin with heat producing sediments.



                             7.12 Lithospheric extension and decompression melting
                 We have seen that extension and crustal thinning lead to upwelling of hot mantle rocks. If
                 mantle rocks are brought up to sufficiently shallow depths the temperature may cross the
                 solidus, which is the temperature where the rocks start to melt. Figure 7.22 shows a situa-
                 tion where rapid lithospheric extension has caused mantle rocks to cross the solidus. Mantle
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