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Processing of Plastics                                         26 1

                 barrel of the extruder in this case), the principal stresses which exist as a result
                 of an internal pressure are

                                                       PmmD
                                       hoop stress, 01  =
                                                         2h
                                                       ~
                                                       PmaxD
                                        axial stress, a2 = -
                                                         4h
                 where h = wall thickness of the barrel.
                   The von Mises criterion simply states that yielding (failure) will occur if




                 where             ay = tensile yield stress of  material
                                   FS = factor of  safety.

                 In this case, therefore


                                                                   8h2
                                 h = 9.8 mm
                 Hence a barrel wall thickness of  10 mm would be appropriate.
                   Example 4.2  A single screw extruder is to be used to manufacture a nylon
                 rod 5 mm in diameter at a production rate of  1.5 ndmin. Using the following
                 information, calculate the required screw speed.
                           Nylon                   Extruder               Die
                 Viscosity = 42.0  Ns/m2    Diameter = 30  mm       Length = 4  mm
                 Density (solid) = 1140 kg/m3  Length = 750  mm     Diameter = 5  mm
                 Density (melt) = 790  kg/m3   Screw flight angle = 17.7"
                                            Metering channel
                                                depth = 2.5  mm

                 Die swelling effects may be ignored and the melt viscosity can be assumed to
                 be constant.
                   Solution The output rate of  solid rod = speed x cross-sectional area
                                                   = 1.5 x ~(2.5 1OW3)*/60
                                                                x
                                                   = 49.1 x     m3/s
                 As the solid material is more dense than the melt, the melt flow rate must be
                 greater in the ratio of the solid/melt densities. Therefore

                   Melt flow rate through die = 49.1 x  lop6 (g) = 70.8 x    m3/s
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