Page 404 - Power Electronics Handbook
P. 404

Electrical machine control   393
                     Instead of segmenting the rotor it is possible to attenuate the quadrature
                   axis flux by using flux guides or barriers, as in Figure 14.44. Two forms are
                   illustrated here, in both cases it being seen that the quadrature axis flux is
                   decreased to a greater extent than the direct axis flux, due to the position
                   of the guides.
                     It has been seen by  the above discussion that a reluctance motor is in
                   effect a synchronous machine with unexcited rotor poles. Both machines,
                   on the other hand, behave like an induction motor during run-up periods,
                   and  can  be  considered  as special cases of  the  induction  machine.  The
                   torque on the rotor of  an induction motor is caused by induced currents
                   produced by a rotating stator field. If Nl and N2 are the speeds of this field
                   and of  the rotor respectively, then the slip S is defined by  equation (14.5).
                         Nl  - N2
                     S=                                                       (14.5)
                            Nl
                     The magnitude  of  the  rotor  torque  is  proportional  to  stator  flux,
                   rotor-induced  current  and  the  cosine  of  the  angle  between  these  two
                   phases, being given by equation (14.6) where T is the torque on the rotor, S
                   is the slip, El is the stator applied voltage,f, is the stator frequency, R2 is the
                   rotor resistance and X, is the rotor reactance.

                                                                              (14.6)

                     Tar (zy                                                  (14.7)
                     Equation (14.6) gives the maximum torque T,,, which occurs at a slip S,,
                   derived from equations (14.7) to (14.9).



                          R2
                    s,  a -                                                   (14.8)
                          fl

                    x2 arfl                                                   (14.9)
                     Substituting these values in equation (14.6) gives the result as in equation
                   (14.10).
                             q-r.
                     T=      '                                               (14.10)
                               1,
                          SmlS + SIS,
                    The input power, which crosses the air gap between stator and rotor, is
                  primarily used in producing copper losses and torque output. These two
                  are divided in the ratio of S/( 1 - S) so that motor efficiency is equal to that in
                  equation (14.11).
                     qm=l-S                                                  (14.11)
                     In a commutator motor, as with some types of  induction motors when
                   the  motor  winding  is  brought  out  to  slip rings  and  brushes,  a  resistor
                   connected in series with the rotor would result in power loss. This would
                   mean that the output power of the machine is reduced and it must slow
                   down  to supply  the  same torque.  A  further  advantane  of  mmmlltrrtnr
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