Page 74 - Power Electronics Handbook
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Heatsinks   67

                    the heatsink and P, is the rate of heat flow in watts. The thermal resistance
                    of  the heatsink (&)  is then given by  equation (2.11).
                           kTadT
                      Pc  = -                                                  (2.10)
                              d




                          =-  d                                                (2.11)
                            kT a
                    connctioll. Convection may be due to natural air flow or forced air flow.
                    Forced convection is further dependent on whether the air flow is laminar
                    or turbulent. At low air velocities the flow is laminar and this changes at
                    higher  velocities  to  turbulent,  the  actual  point  of  changeover  being
                    dependent on the design of the heatsink.
                      The heat flow from the heatsink having a cross-sectional area of  a, a
                    vertical length of I, and a temperature difference above the surrounding of
                    dT, is given empirically by equation (2.12).

                                                                               (2.12)

                    where the constant k,  has a value of  about 1.37.
                      If  the heatsink is now cooled by forced air, having a velocity of  v,,  then
                    the heat flow for laminar and turbulent air flow are given by  equations
                    (2.13)  and (2.14)  respectively, where the constants have the approximate
                    values kfl = 3.9  and kft = 6.0.
                      Pn  = kaadT (7)                                          (2.13)
                                       M


                     Pn = knadTF V.0.8
                                                                               (2.14)
                    Rdhtion. The heat loss due to radiation is dependent on the emissivity of
                    the heatsink  (E)  and its temperature difference above the ambient. The
                    maximum value of emissivity is unity, that of  a black body radiator. If  TI
                    and T2 are the temperatures of the surface of the heatsink and that of the
                    surrounding air, then  the heat  loss  in  watts  due  to  radiation*is given  by
                    equation  (2.15) where  the  constant  k, is  approximately equal  to  5.7  X
                    lo-*.
                     P, = k,ae(T:  - a)                                       (2.15)
                     Thermal analysis using the equations given above can result in errors up
                   to 25%  since many factors affect the actual heat-dissipation properties of
                   heatsinks. The errors arise due to:
                   (i)  The mix  of  heat transfer modes and the difficulty of  predicting the
                        actual heat transfer path. Heat radiating from adjacent bodies also
                        grossly affects the final result.
                   (ii)  The variation in power  dissipation between semiconductors of  the
                        same type,  even  when  these  come  from  the  same  batch.  Power
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