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454 9. Confidence Interval Estimation
x = 0. We may assume that a > h since we have 0 < α < ½. Since we have
P(a < X < a) = P(a g < X < a h), one obviously, has
But, the pdf f(x) is symmetric about x = 0 and f(x) is assumed positive for all
x ∈ ℜ. The Figure 9.2.7 describes a situation like this. Hence, the integrals in
(9.2.15) can be equal if and only if which can
happen as long as the interval (a h, a) is shorter than the interval (a, a +g).
The result then follows. The details are left out as an exercise. !
Remark 9.2.1 The Theorem 9.2.1 proved that among all (1 α) intervals
going to the left of (a, a), the interval (a, a) was the shortest one. Since,
f(x) is assumed symmetric about x = 0, it also follows from this result that
among all (1 α) intervals going to the right of (a, a), the interval (a, a) is
again the shortest one.
Example 9.2.12 (Example 9.2.7 Continued) The length L of the confi-
n
dence interval from (9.2.9) amounts to 2z n σ which is the shortest width
½
α/2
2
among all (1 α) confidence intervals for the unknown mean µ in a N(µ, σ )
population with σ(> 0) known. The Theorem 9.2.1 immediately applies. Also
½
observe that the shortest width, namely 2z n σ, is a fixed number here.
α/2
Example 9.2.13 (Example 9.2.8 Continued) The length L of the confi-
n
½
dence interval from (9.2.10) amounts to 2t n1,α/2 n S which is a random vari-
able to begin with. So, we do not discuss whether the confidence interval
from (9.2.10) has the shortest width among all (1 α) confidence intervals
for the unknown mean µ. The width L is not even a fixed number! Observe
n
that where Y has the distribution. But,
the expression for is a function of n only. Now, Theorem 9.2.1 di-
rectly implies that the confidence interval from (9.2.10) has the shortest ex-
2
pected width among all (1 a) confidence intervals for µ in a N(µ, s ) popu-
2
lation when σ (> 0) is also unknown. !
Both examples handled the location parameter estimation problems and we
could claim the optimality properties (shortest width or shortest expected width)
associated with the proposed (1 α) confidence intervals. Since the pivotal
pdfs were symmetric about zero and unimodal, these intervals had each tail
area probability ½α. Recall the Figures 9.2.49.2.5.
In the location parameter case, even if the pivotal pdf is skewed but
unimodal, a suitable concept of optimality of (1 α) confidence intervals
can be formulated. The corresponding result will coincide with Theorem

