Page 118 - Process Equipment and Plant Design Principles and Practices by Subhabrata Ray Gargi Das
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4.7 Design illustration  115




                  Substituting the values in Eq. (3.3), the overall heat transfer coefficient is

                    1                 1        0:00018   0:0254        4         0:0254
                                                              þ 1:1   10  þ
                    U             1389:0236        0:01859                 8020:8236   0:01859
                      ¼ 0:00018 þ
                                            þ
                                      2
                                    m K
                                   3
                      ¼ 1:4262   10
                                     W
               or U ¼ 701:15  W
                              2 , which is almost same as the assumed value. So design is Ok (no over design).
                            m K
                  Using Kern’s method for pressure drop calculation, Dp t for tube-side fluid can be obtained from
               Eq. (4.23) where f t can be obtained from Eq. (3.16a) for turbulent flow in tubes (with  5% tolerance) as
                                               0:32             0:125               3
                                                                      0:32
                           f t ¼ 0:0014 þ 0:125=ðReÞ  ¼ 0:0014 þ         ¼ 5:16   10
                                                             ð57031:24Þ
                  Thus,
                                                                                 3
                      1                                              4   5:16   10    6   2
                          2   4f t L p N p                      2
                        t t
                Dp t ¼  r u          þ 4N p ¼ 0:5   992:22  ð1:985Þ                      þ 8
                      2         D i                                        0:01859
                                                                     2           2
                                            ¼ 302.124 kPa ¼ 0.425 kg=cm  < 0:7kg=cm limit
                                                                      6
                  For shell-side fluid, Re s ¼ 30862:344 and since 400 < Re s   10 , f from Eq.(4.25) is
               f ¼ exp f0:576   0:19   lnðRe s Þg ¼ exp f0:576   0:19   lnð30862:344Þg ¼ 0:2484.
                                                                        L     6
                                                                                  ¼ 24:5z25 and
                  For baffle spacing B ¼ 0:2445, number of baffles N b ¼    ¼
                                                                        B   0:2445
               N b þ 1 ¼ 26.
                  Since for two tube passes nozzles are on opposite side and ðN b þ1Þ is odd, we consider N b þ 1 ¼ 27.
                  This gives pressure drop from Eq. (4.24) as
                           2                             2
                         f s G ðN b þ 1ÞD s  0:2484  ð453:858Þ   27   0:489
                           s
                  Dp s ¼              ¼                               ¼ 25912:134
                             2r De             2   710   0:01836
                               s
                              2             2
               Pa ¼ 0.26 kg cm   < 0.7 kg cm .
                  So the pressure drop for both tube and shell side is within the maximum allowable pressure drop
               specified in the problem.
                  For D s ¼ 489 mm, the minimum bundle to shell clearance for easy pull out of bundle in case of
               fixed tube is 10 mm from Table 4.11 and from Table 4.18, nominal nozzle diameter is 101.6 mm (4 ).
                                                                                               00
               From Table 4.19, the nozzles are fabricated from Schedule 80 pipe with a corrosion allowance of
               3 mm.
                                                         p          2            3  2
                                                           ð0:1016Þ ¼ 8:107   10  m
                                                         4
                           Nozzle cross sectional area A nozzle ¼
                  And velocity of entering shell-side fluid through nozzle
                        m s         10:8472
                                                 ¼ 1:8844 m s.
               u s;in ¼      ¼                 3
                      r A nozzle  710   8:107   10
                       s
                                                    2
                                                                 kg
                  This gives r s;in    u 2 s;in  ¼ 710  ð1:8844Þ ¼ 2521:287  ms 2.
                  This is slightly higher than the limit for noncorrosive, nonabrasive, single-phase fluid, 2230  kg
                                                                                              ms 2
               impingement. However, for this design, impingement baffle is not included as the limit is exceeded
               only by a small value.
                  We adopt single segmental baffle with 25% cut. As per IS 4503, from Table 4.14 for D s > 400 and
                 700 and distance between adjacent baffles > 150 and   300, baffle thickness is 4 mm.
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