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222        Process Modelling and Simulation with Finite Element Methods


          with  fully  developed  laminar  Hagen-Poiseuille  flow  gives  Ap=60.  The  fully
          developed u-velocity profile is

                                 24  = 6U,,,,Y   (1-  Y)               (6.5)

          Substitution into  (6.2) yields  the constant pressure  gradient  as -12  Urn,,,. Over
          five  unit  lengths  downstream,  one  would  expect pinler=60Umean on  the  inflow
         plane  to  achieve p=O  at  the  outflow.  So  the  additional  pressure  drop  over
          Hagen-Poiseuille flow is 0.463 (unitless due to scaling of viscosity and velocity).

         Exercise 6.1
          Refine  the mesh  and  compute the  additional  pressure  drop.  Use the  standard
          refinement  on the toolbar,  and restart  with the old  solution as the initial guess.
          Comment  on  the  uniformity  of  the  mesh  and  the  variation  in  the  additional
         pressure drop. Is it worth refining the mesh yet again?
         Now  go to  Draw Mode,  and  double click on the vertices  at the bottom of the
          notch.  Edit them to place the orifice plate  across to 40% blockage of  the gap,
          but  with  the  same  width  (0.05).  Solve.  Figure  6.4 shows  the  arrow plot  of
          velocity  vectors.  Clearly  the  velocity  profile  must  “turn  the  corner”,  which
         causes  substantially  more  disruption  and  by  implication  more  dissipation  of
          energy.

                            Arrow: [x velocity (u),y velocity (v)]  epsilon=O 4
                                                           t
                         2   ’










                         ff
                     Figure 6.4  Velocity vector arrow plot for blockage factor &=0.4

         Boundary  integration  gives  a pressure  loss of  Ap=84.866  required  to  achieve
         uniform  outflow with  p=O.  Note  that  boundary  integration  along  the  outflow
         boundary  of  the  x-velocity  gives  1, the  value  of  U,,,,.   Figure  6.5 shows  the
         isobars which clearly show rapid dissipation of pressure in the orifice.  Also, just
         upstream  of  the plate,  the maximum  pressure  occurs, due to  the need  to force
         flow “around the corner.”
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