Page 202 - Schaum's Outline of Theory and Problems of Advanced Calculus
P. 202

CHAP. 8]               APPLICATIONS OF PARTIAL DERIVATIVES                      193

                                                                                           y
                      8.9. (a) Find the envelope of the family x sin   þ y cos   ¼ 1. (b) Illus-
                           trate the results geometrically.
                           (a)ByProblem 8 the envelope, if it exists, is obtained by solving simulta-
                              neously  the  equations   ðx; y; Þ¼ x sin   þ y cos     1 ¼ 0  and
                                  ðx; y; Þ¼ x cos     y cos   ¼ 0.  From these equations we find       x
                                                   2
                                                2
                              x ¼ sin  ; y ¼ cos   or x þ y ¼ 1.
                           (b) The given family is a family of straight lines, some members of which
                                                                    2
                                                                        2
                              are indicated in Fig. 8-5. The envelope is the circle x þ y ¼ 1.
                                                                                          Fig. 8-5
                                                                       2
                     8.10. Find the envelope of the family of surfaces z ¼ 2 x   a y.
                              By a generalization of Problem 8.8 the required envelope, if it exists, is obtained by solving simulta-
                           neously the equations
                                                      2
                                                ¼ 2 x     y   z ¼ 0  and       ¼ 2x   2 y ¼ 0
                                          ð1Þ                          ð2Þ
                                                                 2
                           From (2)   ¼ x=y.  Then substitution in (1)yields x ¼ yz,the required envelope.

                     8.11. Find the envelope of the two-parameter family of surfaces z ¼  x þ  y     .
                              The envelope of the family Fðx; y; z; ;  Þ¼ 0, if it exists, is obtained by eliminating   and   between the
                           equations F ¼ 0; F   ¼ 0; F   ¼ 0 (see Problem, 8.43).  Now
                                       F ¼ z    x    y þ    ¼ 0;  F   ¼ x þ   ¼ 0;  F   ¼ y þ   ¼ 0
                           Then   ¼ x,   ¼ y; and we have z ¼ xy.



                     DIRECTIONAL DERIVATIVES

                                                                               u
                                                            3
                                                          2
                     8.12. Find the directional derivative of F ¼ x yz along the curve x ¼ e , y ¼ 2 sin u þ 1, z ¼ u   cos u
                           at the point P where u ¼ 0.
                              The point P corresponding to u ¼ 0is ð1; 1;  1Þ.  Then
                                                           2 3
                                                                 2
                                                                   2
                                                       3
                                               rF ¼ 2xyz i þ x z j þ 3x yz k ¼ 2i   j þ 3k at P
                              Atangent vector to the curve is
                                              dr  d   u
                                              du  ¼  du  fe i þð2 sin u þ 1Þj þðu   cos uÞkg
                                                     u
                                                ¼ e i þ 2cos uj þð1 þ sin uÞk ¼ i þ 2j þ k at P
                                                                  i þ 2j þ k
                                                                         :
                           and the unit tangent vector in this direction is T 0 ¼  p ffiffiffi
                                                                     6
                              Then

                                                                           i þ 2j þ k  3  1 p ffiffiffi
                                                                                            6:
                                                                                       ffiffiffi
                                    Directional derivative ¼rF   T 0 ¼ð 2i   j þ 3kÞ   p ffiffiffi  ¼ p ¼
                                                                              6        6  2
                           Since this is positive, F is increasing in this direction.
                     8.13. Prove that the greatest rate of change of F, i.e., the maximum directional derivative, takes place in
                           the direction of, and has the magnitude of, the vector rF.
   197   198   199   200   201   202   203   204   205   206   207