Page 109 - Schaum's Outline of Theory and Problems of Electric Circuits
P. 109

AMPLIFIERS AND OPERATIONAL AMPLIFIER CIRCUITS
               98
                     The rate of change of G with respect to A is                               [CHAP. 5

                                           dG      1                         dA
                                              ¼           from which   dG ¼
                                           dA   ð1 þ AÞ 2                  ð1 þ AÞ 2
                     The percentage change produced in G is 100ðdG=GÞ.

                                                dG     dA    1 þ A    1   dA
                                                   ¼              ¼
                                                 G   ð1 þ AÞ 2  A   1 þ A  A
                     and the sensitivity is
                                                          dG=G     1
                                                       s ¼     ¼
                                                          dA=A   1 þ A
                     The percentage change in G depends on A.  Samples of dG=dA and s are shown in Table 5-8.

                                                        Table 5-8
                                            A      G ¼ v 2 =v 1  dG=dA   s
                                             10      0.909    0.008    0.091
                                             11      0.917    0.007    0.083
                                            100      0.990    0.0001   0.01
                                            1000     0.999    0        0


                         For high values of A, the gain G is not sensitive to changes in A.







                                             Supplementary Problems


               5.30  Repeat Problem 5.3 by replacing the circuit to the left of node B (including v s , R 1 , and R i ) by its The ´ venin
                     equivalent (see Fig. 5-33)  Solve the problem by applying the results of Example 5.4.

               5.31  Find the The ´ venin equivalent of the circuit to the left of nodes A-B in Fig. 5-52 with k ¼ 10 for (a) R 2 ¼1
                     and (b) R 2 ¼ 50 k
.  Ans:  ðaÞ v Th ¼ 100 V; R Th ¼ 100 
;  (bÞ v Th ¼ 31:22 V; R Th ¼ 37:48













                                                        Fig. 5-52


               5.32  Repeat Problem 5.31 for R 2 ¼ 50 k
 and k ¼ 100.  Ans:  v Th ¼ 47:16 V; R Th ¼ 5:66



               5.33  Determine the relationship between R, R 1 , and R 2 in Fig. 5-41 such that the circuit has a gain of
                             6
                     v 2 =i 1 ¼ 10 V/A.  Ans:  RR 2 =R 1 ¼ 10 6
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