Page 292 - Semiconductor For Micro- and Nanotechnology An Introduction For Engineers
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Inhomogeneities
                             so that we can write that
                                                       2
                                                             2
                                                      ∂ ψ   ∂ φ
                                              ε  =  –  ------------ +  --------  (7.116a)
                                               11
                                                     ∂x∂z     2
                                                            ∂x
                                                            2
                                                      2
                                                     ∂ ψ   ∂ φ
                                              ε  =  –  --------- +  ------------  (7.116b)
                                              13       2
                                                     ∂z    ∂z∂x
                                                                   2
                                                    2
                                                             2
                                              2
                                             ∂ ψ   ∂ φ      ∂ ψ   ∂ φ
                                       ε  =  --------- +  ------------ =  –  --------- +  ------------  (7.116c)
                                        31     2              2
                                             ∂x    ∂x∂z     ∂z    ∂x∂z
                                                            2
                                                      2
                                                     ∂ ψ   ∂ φ
                                              ε 33  =  ------------ +  --------  (7.116d)
                                                    ∂z∂x   ∂z 2
                             We can write the stress as  σ =  C:ε   in tensor notation or use the more
                             compact Voight engineering notation. For silicon, which possesses cubic
                             crystal symmetry,
                                     σ  11  C  11  C  12  C 12       ε 11
                                     σ 22   C 12  C 11  C 12          0
                                     σ      C   C   C                ε
                                      33      12  12  11              33
                                         =                         ⋅            (7.117a)
                                     σ                 C              0
                                      23                 44
                                     σ                     C         2ε
                                      31                    44         31
                                     σ                         C      0
                                      12                        44
                                                 C ε +  C ε
                                                          12 33
                                                  11 11
                                                 C ε +  C ε
                                                  12 11
                                                          12 33
                                                 C ε +  C ε
                                                          11 33
                                                  12 11
                                              =                                 (7.117b)
                                                       0
                                                    2C ε
                                                       44 31
                                                       0
                             Substituting (7.116a)-(7.116d) into (7.117a) gives




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