Page 288 - Semiconductor For Micro- and Nanotechnology An Introduction For Engineers
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Inhomogeneities
                                                                        
                                          1
                                                             
                                                    (
                                    u  =  --------c exp   jk +  jk )ai –  1   ωt   (7.104a)
                                                                 --- –
                                                 
                                     m       m        1    2    4 
                                          m                            
                                          1                    1      
                                                    (
                                   u  =  ---------c exp   jk +  jk )ai +  --- –  ωt   (7.104b)
                                    M        M        1    2    4 
                                          M                             
                             so that the solutions become
                                                     2
                                                    ω =
                                E                    2                           (7.105)
                                           −
                              ------------- M +( [  m) +  ( M +  m) –  2Mm 1 –  cos  ( [  k +  jk )a])]
                                                            (
                                                                          2
                                                                      1
                              aMm
                             With the identity
                             cos  ( [  k +  jk )a] =  cos ( k a)cosh ( k a) –  jsin ( k a)sinh ( k a)  (7.106)
                                   1    2          1       2         1        2
                             we find a condition for real ω
                                             sin ( k a)sinh ( k a) =  0          (7.107)
                                                          2
                                                  1
                             Clearly, setting k =  0   gives the result for a bulk lattice. For k ≠  0  , we
                                          2
                                                                               2
                                                             −
                                                              1 +
                                                   ⁄
                                                            ,
                             must have that  k =  iπ a  ,  i =  0 + ,  − 2 …,  .  Thus the solution
                                             1
                             becomes
                                                     2
                                                    ω =
                               E                    2                            (7.108)
                                          −
                             ------------- M +( [  m) +  ( M +  m) –  2Mm 1 –  cos ( k a)cosh ( k a))]
                                                           (
                                                                    1
                                                                            2
                             aMm
                                     ω
                             as long as   is real. This condition is not fulfilled everywhere. In partic-
                                                            ⁄
                             ular, at some value k   for k =  − π a   the frequency becomes
                                                         +
                                             2max    1
                                                         1
                                                             1
                                              ω 2  =  E   ----- +  ----        (7.109)
                                                     ---
                                               k 2max  a  M  m 
                             beyond which no frequency is defined. This is clearly seen on the disper-
                             sion “surface” of Figure 7.13. In the range  0 ≤  k ≤  k   we observe a
                                                                    2   2max
                             completely filled band between the acoustic and optical branch of the dis-
                             Semiconductors for Micro and Nanosystem Technology    285
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