Page 251 - Separation process engineering
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(6-6)

                    Equations (6-4) and (6-5) are valid for all stages in the column, 2 ≤ j ≤ N − 1, and are repeated for each
                    of the C components. If a stage has no feed, then F = D = 0.
                                                                             j    j
                    For a total condenser, the mass balance is




                                                                                                                                  (6-7)

                    Since x  = x  y  = K x  and x  =  /L , this equation becomes
                                  D, 2
                                            2 2
                            1
                                                           1
                                                      1
                                                              1
                                                                                                                                  (6-8)
                    where




                                                                                                                                  (6-9)

                    Note that only B  does not follow the general formulas of Eq. (6-6). This occurs because the total
                                      1
                    condenser is not an equilibrium contact.
                    For the reboiler, the mass balance is




                                                                                                                                (6-10)

                    Substituting y  = K x  and   = L x  = Bx , we get
                                                                      bot
                                          N N
                                   N
                                                           N N
                                                     N
                                                                                                                                (6-11)
                    where






                                                                                                                                (6-12)

                    In matrix notation, the component mass balance and equilibrium relationship for each component is


















                                                                                                                                (6-13)

                    This set of simultaneous linear algebraic equations can be solved by inverting the ABC matrix. This can
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