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                                                                                                         Materials  37
                                               description of strength, a material property, is distributional and thus is statistical in
                                               nature. Chapter 20 provides more detail on statistical considerations in design. Here we
                                               will simply describe the results of one example, Ex. 20–4. Consider the following table,
                                               which is a histographic report containing the maximum stresses of 1000 tensile tests on
                                               a 1020 steel from a single heat. Here we are seeking the ultimate tensile strength S ut . The
                                               class frequency is the number of occurrences within a 1 kpsi range given by the class
                                               midpoint. For example, 18 maximum stress values occurred in the range of 57 to 58 kpsi.

                       Class Frequency f i  2  18  23  31  83  109  138  151  139  130  82   49   28   11   4    2

                        Class Midpoint  56.5 57.5 58.5 59.5 60.5 61.5 62.5 63.5 64.5 65.5 66.5 67.5 68.5 69.5 70.5 71.5
                           x i , kpsi

                                                  The probability density is defined as the number of occurrences divided by the total
                                               sample number. The bar chart in Fig. 2–5 depicts the histogram of the probability den-
                                               sity. If the data is in the form of a Gaussian or normal distribution, the probability
                                               density function determined in Ex. 20–4 is

                                                                                                  2
                                                                          1          1  x − 63.62
                                                               f (x) =    √    exp −
                                                                      2.594 2π       2    2.594

                                               where the mean stress is 63.62 kpsi and the standard deviation is 2.594 kpsi. A plot
                                               of f (x) is also included in Fig. 2–5.  The description of the strength  S ut is then
                                               expressed in terms of its statistical parameters and its distribution type. In this case
                                               S ut = N(63.62, 2.594) kpsi, indicating a normal distribution with a mean stress of
                                               63.62 kpsi and a standard deviation of 2.594 kpsi.
                                                  Note that the test program has described 1020 property S ut , for only one heat of
                                               one supplier. Testing is an involved and expensive process. Tables of properties are
                                               often prepared to be helpful to other persons. A statistical quantity is described by its


                       Figure 2–5                0.2

                       Histogram for 1000 tensile
                       tests on a 1020 steel from a
                       single heat.
                                                                                           f(x)


                                                Probability density  0.1













                                                  0
                                                         50                  60                   70
                                                                      Ultimate tensile strength, kpsi
   57   58   59   60   61   62   63   64   65   66   67