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244                                                  Soil and Water Contamination
                                                                   6955

                             No retardation

                     Concentration         With retardation


                                               (R ∼ 4)

                                                     With retardation
                                                       and tailing

                                          Time
                    Figure 13.3   Breakthrough curves of a conservative substance and a substance subject to linear sorption  or
                    retardation  (solid line). The dotted line represents the breakthrough curve  of a substance subject to non-linear
                    sorption according to a convex isotherm.  Note the self-sharpening tendency of the front and the tailing  at the end of
                    the breakthrough curve.

                    curve derived from a column experiment exhibits ‘tailing ’ and the concentration C = C  is
                                                                                         0
                    reached much later than predicted by Equation (13.10) (see Figure 13.3). In the case of an
                    accidental release of a chemical into groundwater, this may lead to much slower removal of the
                    chemical from the aquifer  than was predicted using a linear adsorption  isotherm. A concave
                    isotherm causes low concentrations to be transported faster and has the reverse effects: the
                    breakthrough front is spread out and the declining limb of the breakthrough curve is relatively
                    steep. Nevertheless, sorption is most commonly modelled with a single parameter (K  or R ),
                                                                                      d   f
                    because this is easy to implement in chemical transport models. Figure 13.4 shows the plume
                    in groundwater of a substance subject to sorption. Comparison with Figure 11.10 shows that
                    the contaminant has been transported downstream for only about half the distance compared
                    to an inert substance that undergoes advection  and dispersion  only. This implies that in this
                    case the retardation factor R is about 2.
                                         f
                       Example 13.1  Retardation

                       An aquifer  underneath a waste disposal site is contaminated by 1,4-dichlorobenzene,
                       a chlorinated hydrocarbon commonly used as an air freshener for toilets and refuse
                       containers, and as a fumigant for control of moths, moulds, and mildews.  The log

                       octanol–water partition coefficient  for 1,4-dichlorobenzene is log K  = 3.43. The aquifer
                                                                           ow
                                                -3
                       has a bulk density  of 1675 kg m , a porosity  of 0.3, and an organic carbon  content of 0.1
                                                                                   -1
                       percent. The groundwater flows at an average horizontal velocity of 50 m y . Estimate
                       the horizontal velocity of the 1,4-dichlorobenzene plume  .
                       Solution
                       First, estimate the organic carbon–water partition coefficient  K   using the empirical


                                                                          oc
                       relationship between K  and K  listed in Table 13.1:
                                        oc    ow
                       log K     . 0  937  log K  . 0  006    . 0  937  . 3  43  . 0  006    . 3  21
                            oc           ow
                       K     1614  l kg -1
                        oc
                       Second, use Equation (13.4) to estimate the distribution coefficient K :

                                                                            d
                                                        -1
                                                                  -3
                                                                      3
                       K    f  K     . 0  001  1614    . 1  614 l kg  = 1.614·10  m  kg -1
                        d    oc  oc



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        Soil and Water.indd   256                                                           10/1/2013   6:45:11 PM
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