Page 199 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 199

186                               Properties of Vibrating Systems   Chap. 6

                             If A,  ^   the  foregoing equation  requires that
                                                                                         (6.6-6)

                             It  is  also  evident  from  Eq.  (6.6-2)  or  Eq.  (6.6-3)  that  as  a  consequence  of  Eq.
                             (6.6- 6),
                                                      4>]K4>^  =  0   i ^ j              (6.6-7)
                             Equations (6.6-6) and (6.6-7) define the orthogonal character of the normal modes.

                                  Finally,  if  /  = j\  (A,  —A^)  == 0  and  Eq.  (6.6-5) is  satisfied  for  any finite value

                             of the  products given by  Eq.  (6.6-5) or (6.6-6).  We  therefore  have
                                                               = M,,
                                                                                         (6.6-8)
                                                         ct>jKcf>,  =
                             The  quantities  M-  and  K-  are  called  the  generalized  mass  and  the  generalized
                             stiffness, respectively. We will have many occasions to refer to the generalized mass
                             and  generalized  stiffness  later.
                             Example 6.6-1
                                  Consider  the  problem  of  initiating  the  free  vibration  of  a  system  with  a  specified
                                  arbitrary  displacement.  As  previously  stated,  free  vibrations  are  the  superposition  of
                                  normal  modes,  which  is  referred  to  as  the  Expansion  Theorem.  We  now  wish  to
                                  determine  how  much  of each  mode will  be present  in  the  free vibration.
                             Solution:  We will  express first  the  arbitrary displacement  at time zero by the  equation;
                                               3f(0)  =  c^(f) I  +  C2</)2  +  C^(j)^  -f  •  •  •   +  •  •  •
                                 where  (/>,  are  the  normal  modes  and   are  the  coefficients  indicating  how  much  of
                                  each  mode  is  present.  Premultiplying the  above  equation  by (¡)JM  and  taking note  of
                                  the  orthogonal  property of  (/>,, we obtain,
                                                      = 0 + 0 + 0 +  • ••   + 0 +  • • •

                                 The  coefficient  c,  of any mode  is then  found  as
                                                              </>fMX(0)
                                                          C:  =   -----7---------


                                  Orthonormal  modes.  If  each  of  the  normal  modes   is  divided  by  the
                             square  root  of  the  generalized  mass  M-,  it  is  evident  from  the  first  equation  of
                             Eqs.  (6.6-8)  that  the  right  side  of  the  foregoing  equation  will  be  unity.  The  new
                             normal  mode  is  then  called  the  weighted  normal  mode  or  the  orthonormal  mode
                             and  designated  as   It  is  also  evident  from  Eq.  (6.6-1)  that  the  right side of the
                             second  equation  of Eq.  (6.6-8) becomes equal  to the  eigenvalue  A,. Thus,  in place
                             of Eqs. (6.6-8),  the  orthogonality in  terms of the  orthonormal  modes becomes
                                                         ^JM^,  =  1
                                                                                         (6.6-9)
                                                               = À,
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