Page 197 - Thomson, William Tyrrell-Theory of Vibration with Applications-Taylor _ Francis (2010)
P. 197

184                               Properties of Vibrating Systems   Chap. 6









                                                         Figure 6.5-2.



                             Solution:  Compared  to the previous  Example 6.4-1, we now have an additional coordinate
                                  ^3,  which  results  in  a  4  X  4  matrix.  To  the  three  configurations  of  the  previous
                                  problem,  we  add  the  fourth  configuration,  as  shown  in  Fig.  6.5-2.  The  new  4 x 4
                                  stiffness  is easily determined  and  is given as


                                                 ' F ^    ■ 24  6  6  1  6  ■ 'vF
                                                            /2  /   /  I    /
                                                                     1
                                                                     1
                                                 M,         6   8      0
                                                       E l  /      2  1 1
                                                    '  '   'T  6     1    <
                                                                2  8  1  2  02
                                                 M 2        T
                                                                     1
                                                                     1
                                                            6
                                                 M 2        7   0   2  1 4  0,
                                                    J                1    \
                                 which we  partition by the  dotted lines and relabel  as
                                                                  1^,2
                                                                                          (6.5-1)
                                                              a:2,  1K 22
                                 Note here that   is the stiffness matrix of the previous problem. Multiplying out the
                                 new  matrix, we obtain


                                                         SOI  =   K 2 , V  +  K 22&       (6.5-2)
                                  Because  for  the  pinned  end,  the  moment  is  zero,  we  let   =  0  and  solve  for  0   in
                                  terms of the  other coordinates,  thus  reducing the  size of the 4 x 4   matrix to  a 3  X  3
                                 matrix.
                                                          0  =  -K22'K2,V                (6.5-3)

                                  Substituting this  into the  first equation, we  have
                                                      d =  {K,,-K,2K22'K2,)V             (6.5-4)

                                  Because  the  first  term  of this equation  is that  of the  previous example, we  need only
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