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234     Mathematica Solutions to Problems































         1.3 Plot the average binding WHof hydrogen ions by ATP at 298.15 K and 0.25 M ionic strength as a function of pH at pMg
         = 2, 3 4, 5, and 6.

                 klATP = 3.43 * 10 " -7;
                 k2ATP= 0.000140;
                 k3ATP=0.000122;
                 k4ATP=0.0110;
                 k5ATP=O.O279;


         The binding polynomial is given by

                 g= 1+ (10A-gH)  /klATP+  (10" (-2*pH))  / (klATP*k2ATP)  +  (10"-gMg)  /k3ATP+
                   ((IOA-gH)  * (lO"-pMg))  /  (klATP*k4ATP)  +  (10" (-2*PMg))  /  (k3ATP*kSATP)

                              10              6
                     1.9699 10      2.91545  10              8    -pH -  pMg   293789.   8196.72
                1+               +              +  2.47072 10  10           +-+-
                       lo2 pH          loPH                                   102 PMg     1 OPMg

         The average binding of hydrogen ions is given by

                 nH =  -D[Log[g],  pH]  /Log[lO]
                                          10  1 -  2 pH              6
                              -4.53586 10    2            6.71308 10                8   -pH -  pMg
                                                        -              -  5.68905 10  10
                                        52 PH
                                                             1 OPH
                                  1u              b
                        1.9699 10    +  2.91545 10               8   -pH -  pMg   293789.   8196.72
                   (1 +                             +  2.47072 10  10           +-+-                )  Log[lOl
                                                                                  102 PMg
                          lo2 pH          1 OPH                                               1 OPMg
                 Plot[Evaluate[nH/.  [pMg+  [2,  3,  4,  5,  6}}],  [pH, 3,  9}, AxesLabel+  ["pH",  llNH"}];
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