Page 314 - Thermodynamics of Biochemical Reactions

314 Mathernatica Solutions to Problems

PH 5 PH 6 PH 7 PH 8 PH 9
I=OM -1.64496 -1.15373 -1.01784 -1.00181 -1.00018
I = 0.10 M -1.40356 -1.06337 -1.00672 -1.00068 -1.00007

I = 0.25 M -1.3297 -1.04688 -1.00489 -1.00049 -1.00005
Net reaction for the citric acid cycle

TableForm[Transpose[calctrGerx[acetylcoA+3*nadox+fadenzox+adp+pi+4*h2o+de==2*co2tot+3*n
adred+fadenzred+atp+coA, {5,6,7,8,9), {O, .l, .25)1 I .TableHeadings->{{"I = 0 M"."I = 0.10
M","I = 0.25 M1'I,{"pH 5'1,"pH 6",1mpH 7","pH 8","pH 9"))l
PH 5 PH 6 PH 7 PH 8 PH 9
I=OM 1.07855 -17.0051 -39.0265 -62.5329 -88.5914
I = 0.10 M -8.39957 -27.2695 -49.6119 -73.7693 -100.965

I = 0.25 M -11.5591 -30.641 -53.1761 -77.5161 -105.074
TableForm[Transpose[calck~rime[acetylcoA+3*nadox+fadenzox+ad~+p~+4*h2o+de==2*co2tot+3*n
adred+fadenzred+atp+coA,{5,6,7,8,9},{O,.l,.25~~l,Table~eadings-~{~"I = 0 M","I = 0.10
M","I = 0.25 M"),{"pH 5","pH 6","pH 7","pH 8","pH 9"))l
PH 5 PH 6 PH 7 PH 8 PH 9
6 10 15
I=OM 0.647214 953.103 6.87231 10 9.02059 10 3.31471 10
8 12 11
I = 0.10 M 29.6165 59893.3 4.91554 10 8.38962 10 4.87771 10

9 13 18
I = 0.25 M 105.938 233370. 2.07014 10 3.80323 10 2.55874 10

TableForm[(1/(8.3145l*.298l5*Log[lOl))*D[(2*co2tot+3*nadred+fadenzred+at~+coA-
acetylcoA-3*nadox-fadenzox-ad~-pi-4*h2o),pHl/.is-~{O,.l,.~~}/.~H-
=
>{5,6,7,8,9},TableHeadings->{{"I = 0 M1l,nlI 0.10 M"."I = 0.25 M*tl,{llpH 5","pH 6","pH
711,vigH 811,"gH 911))]
PH 5 PH 6 PH 7 PH 8 PH 9
I=OM -2.9362 -3.48762 -4.08556 -4.24612 -4.88442
I = 0.10 M -3.08649 -3.61864 -4.0978 -4.44174 -5.09714
I = 0.25 M -3.1151 -3.66458 -4.11986 -4.49046 -5.18546

Net reaction for the pyruvate dehydrogenase reaction plus the citric acid cycle (10 reactions)

TableForm[Transgose[calctrGerx[pyruvate+4*nadox+fadenzox+adp+pi+5*h2o+de==3*co2tot+4*na
dred+fadenzred+atp, {5,6,7,8,9), {O, .l, .25)]] ,TableHeadings->{{"I = 0 M","I = 0.10 M","I
= 0.25 M"),{"pH 5","pH 6","pH 7","pH 8","pH 9">?1

PH 5 PH 6 PH 7 PH 8 PH 9
I=OM -22.5548 -41.4116 -66.5906 -94.5908 -123.198
I = 0.10 M -33.3208 -53.3291 -79.3741 -107.845 -137.168
I = 0.25 M -36.9033 -57.2641 -83.6568 -112.221 -141.82

TableForm[Trans~ose[calck~rime[pyruvate+4*nadox+fadenzox+ad~+p~+5*h2o+de==3*co2tot+4*na
dred+fadenzred+atp, {5,6,7,8,9), {O, .l, -2511 ] ,TableHeadings->{ {"I 5 0 M", "1 = 0.10 M", "I
= 0.25 M"),{"pH 5","pH B","pH 7","pH 8","pH 9"))l