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7-36   WATER AND WASTEWATER ENGINEERING

                                Many modifications have been made to the basic equation to account for other alkalinity-
                            contributing species, activity coefficients, and so forth. These are discussed in detail in Schock
                            (1999). The basic equation will be used for the purpose of illustration of its use in design.

                              Stabilization Design for Lime-Soda Softened Water
                             As noted earlier in this chapter, recarbonation is the last step in the softening process. The pur-
                            pose of the recarbonation step is to “stop” the precipitation reaction by lowering the pH. Carbon
                            dioxide addition has been the method of choice for lowering the pH. Other chemicals may be
                            used (for example, H  2  SO  4  ) based on economic and operational considerations. Furthermore, split
                            treatment of groundwater may bring sufficient CO  2   in the bypassed water to lower the pH with-
                            out the addition of purchased chemicals.

                                The objective in stabilization is to achieve an LSI    0. The reactions are given in  Equa-
                            tions 7-27 ,  7-28 ,  7-29  and  7-30.  The equilibrium equations for carbonic acid (7-31 and 7-32)
                            are used to estimate the concentration of CO  2   that must be added. The estimation of the CO  2
                            dose is illustrated in the following example.


                                Example 7-8.   Estimate the dose of CO  2   in mg/L to stabilize the water from split treatment
                            softening. The bypass water has 1.37 meq/L of CO  2  . The estimated constituents and parameters
                            of interest in the blended water are listed in the table below.
                                                         Concentration,
                            Constituent                 meq/L as CaCO 3
                            or parameter                or units as shown
                              2
                            Ca                             1.38
                               2
                            Mg                             0.80
                               2
                            CO                             0.50
                               3
                            HCO                            1.20
                                3
                            pH                             9.95 units
                            TDS                            320 mg/L
                            Temperature                    10	C

                              Solution:
                                  a.  Calculate the LSI.
                                               2
                                    Converting Ca    meq/L to moles /L,
                                                    .
                                                  (1 38 meq/L )(20 mg/meq )           4
                                                                             .
                                                                            690  110   moles/L,
                                                        ,
                                                      40 000 mg/mole
                                                                            2
                                   where 20 mg/meq is the equivalent weight of Ca
                                                     pCa     log (690.   10  4  moles/L  3 16.
                                                                                    )
                                                              2
                                    The alkalinity is the sum of CO  and HCO . The units are given in meq/L. They must
                                                              3         3
                                   be in equiv/L
                                                  pAlk     log (0 50.   10  3   1 20.   10  3 )    2 77.
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