Page 320 - Water and wastewater engineering
P. 320

LIME–SODA SOFTENING 7-37

                  From  Table 7-5  at a temperature of 10 	 C and a TDS of 320 mg/L, the correction factor
                 is 2.56 and the LSI is
                       LSI    pH    pH   995.    3 16    2 77    2 56)    9 95   849    1146
                                                                     .
                                                                           .
                                                 .
                                               (
                                                              .
                                                       .
                                                                                  .
                                     s
                  As expected, this water is unstable and CaCO  3   will precipitate.
              b.  To achieve stability, the pH must be lowered to pH   s   . Using the second dissociation of


                                                               2
                 carbonic acid ( Equation 7-32 ), solve for the ratio [CO ]/[HCO     ] with [H     ]     pH   s    in
                                                               3       3
                 moles/L:
                                                    [H   ][CO 2 3   ]
                                              K a2
                                                     [HCO    ]
                                                           3
                                               [CO 2  ]  K a2
                                                  3

                                              [HCO  3 ]  [H  ]
                  Correcting  K    a 2   for temperature using  Equation 7-34  ,
                                                            .
                                      K a2     10 6 498 2909 39  .     .  /T  0 02379T


                                                        /
                                               .
                                                              .
                                                                  (
                                                      .
                                      K     10 6 498 29909 39283 002379 283)
                                       a2
                                            3 05   10   11
                                             .
                                           2              11
                                       [CO 3  ]     3 05   10    0 0094
                                                  .
                                                                .
                                                       .
                                       [HCO   ]    10  849
                                            3
                 and
                                           [CO 2  ]   0 0094.  [HCO   ]
                                              3                 3
                  The total alkalinity will not change. Only the form of alkalinity will change. The total
                                      3
                                                                  3

                                                  2
                 alkalinity is 0.50     10     equiv/L of CO        1.20     10     equiv/L of HCO . In moles/L
                                                  3                             3
                 these are
                        (0 50   10   3  equiv/L of  CO 2  )(30 g/equiv )
                          .
                                                 3               2 50.   10  4  moles/L
                                       60 gg/mole
                                 3
                         .
                        120   10   equiv/L oof HCO )(61  g/equiv)     . 120   10  3  mooles/L
                                                 3
                                       61  g/mole
                 Thus
                            2                          4                     3
                                       3
                         [CO 3  ]    [HCO ]    2.50   10  moles /L    1.20   10  m moles
                                             1.45    10   3 moles /L

                 This provides two simultaneous equations. Solving for [HCO 3  ],



                                                           .
                                  .
                                 0 0094 HCO[    ] [ HCO ]  1 45 10   3  moles/L
                                             3
                                                      3
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