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244               Well Logging and Formation Evaluation

            Fitting a straight line through the points corresponding to transient
          behaviour yields the model line, given by:

                   -
                                 T T])
            P w = 22 3 0.* (ln  ( [ 24  + )
            Hence the initial reservoir pressure is expected to be 226bar.
            Using Equation 11.30, the product k*h can be estimated:

            L 1 can be taken as 0, with P 1 = 226bar
            L 2 can be taken at 1, with P 2 = 223bar

          Hence:


                           m
                                         * *(
              *
            kh = (12   * )  Q* *( L -  L ) [2 p  P -  P )]
                                               2
                                    2
                                                   1
                                1
                                           2
                                   *
                 = (1  * ) 2  200  (24 *60 60 ) * . * *10 -3  * - ) [2 * .14  * -3 *10 5 ]
                                                     ( 1
                                             1
                                                             3
                                         1
                 =  . 3 686 *10 -13 m 2
          Hence k = 36.86mD.
                    CHAPTER 12: HOMING-IN TECHNIQUES
          Exercise 12.1: Worked Field Example of Magnetostatic Homing In

            Start by entering the survey data from both wells in a spreadsheet. For
          the survey well, derive columns for the x, y and z components of r, the
          vector along the direction of the well bore. Convert these to unit vector
          components by dividing by r.
            Now derive the x, y and z components of unit vectors in the HS and
          HSR directions using equations 12.10 and 12.11.
            Derive the x, y and z components of the Earth’s field using equations
          12.7–12.9. Convert these to the highside reference system using equations
          12.12–12.14.
            Convert the raw tool readings to B hs , B hsr , and B ax . Note that since the
          tool face orientation is along the highside direction (there is no A y com-
          ponent), B x = B hs , B y = B hsr and B z = B ax .
            Derive F xy , F ax , F tot , HS dir and AX dir . You should end up with the fol-
          lowing components:
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