Page 173 - Petroleum Production Engineering, A Computer-Assisted Approach
P. 173

Guo, Boyun / Computer Assited Petroleum Production Engg 0750682701_chap12 Final Proof page 169  4.1.2007 2:43pm Compositor Name: SJoearun




                                                                                  SUCKER ROD PUMPING  12/169
                       the rods. The minimum load is at or near the top of the  or
                       stroke. Neglecting the weight of the plunger and friction  1     2
                       term, the minimum PRL is                  T ¼ SW f þ  2SN W r  (in:-lb):     (12-30)
                                                                    4       70,471:2
                                            W r
                              PRL min ¼ S f (62:4)  þ W r   W r F 2 ,  Because the pumping unit itself is usually not perfectly
                                            g s
                                                                 balanced (C s 6¼ 0), the peak torque is also affected by
                       which, for 50 8API oil, reduces to        structure unbalance. Torque factors are used for correc-
                       PRL min ¼ 0:9W r   F 2 W r ¼ (0:9   F 2 )W r ,  (12:22)  tion:
                                                                    1
                       where for the conventional units          T ¼  2 ½ PRL max (TF 1 ) þ PRL min (TF 2 )Š  ,  (12:31)
                             2
                                 c
                           SN (1   )                                          0:93
                       F 2 ¼     h                        (12:23)  where
                            70,471:2
                       and for air-balanced units                 TF 1 ¼ maximum upstroke torque factor
                                                                  TF 2 ¼ maximum downstroke torque factor
                                 c
                             2
                           SN (1 þ )
                       F 2 ¼     h  :                     (12:24)  0.93 ¼ system efficiency.
                            70,471:2
                                                                   For symmetrical conventional and air-balanced units,
                                                                 TF ¼ TF 1 ¼ TF 2 .
                       12.4.3 Counterweights                       There is a limiting relationship between stroke length
                       To reduce the power requirements for the prime mover, a  and cycles per minute. As given earlier, the maximum
                       counterbalance load is used on the walking beam (small  value of the downward acceleration (which occurs at the
                       units) or the rotary crank. The ideal counterbalance load C  top of the stroke) is equal to

                       is the average PRL. Therefore,                    SN g 1    c
                                                                           2
                                                                 a max = min ¼  h  ,                (12:32)
                                     1
                                  C ¼ (PRL max þ PRL min ):               70,471:2
                                     2
                                                                 (the + refers to conventional units or air-balanced units,
                       Using Eqs. (12.19) and (12.22) in the above, we get  see Eqs. [12.9] and [12.12]). If this maximum acceleration
                           1          1                          divided by g exceeds unity, the downward acceleration of
                       C ¼ W f þ 0:9W r þ (F 1   F 2 )W r  (12:25)  the hanger is greater than the free-fall acceleration of the
                           2          2
                                                                 rods at the top of the stroke. This leads to severe pounding
                       or for conventional units                 when the polished rod shoulder falls onto the hanger

                           1            SN 2  c                  (leading to failure of the rod at the shoulder). Thus, a
                       C ¼ W f þ W r 0:9 þ                (12:26)  limit of the above downward acceleration term divided
                           2           70,471:2 h
                                                                 by g is limited to approximately 0.5 (or where L is deter-
                       and for air-balanced units                mined by experience in a particular field). Thus,

                           1            SN 2  c                  SN 1    c
                                                                   2
                       C ¼ W f þ W r 0:9       :          (12:27)       h  #L                       (12:33)
                           2           70,471:2 h                 70,471:2
                       The counterbalance load should be provided by structure  or
                       unbalance and counterweights placed at walking beam  s ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi
                       (small units) or the rotary crank. The counterweights can  N limit ¼  70,471:2L :  (12:34)
                                                                             c
                       be selected from manufacturer’s catalog based on the cal-  S(1   )
                                                                             h
                       culated C value. The relationship between the counterbal-
                       ance load C and the total weight of the counterweights is  For L ¼ 0.5,
                                                                         187:7
                                              r d 1              N limit ¼ p ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi :    (12:35)
                                     C ¼ C s þ W c  ,                   S(1   )
                                                                             c
                                              c d 2                          h
                       where                                     The minus sign is for conventional units and the plus sign
                                                                 for air-balanced units.
                         C s ¼ structure unbalance, lb
                        W c ¼ total weight of counterweights, lb
                          r ¼ distance between the mass center of counter-  12.4.5 Tapered Rod Strings
                             weights and the crank shaft center, in.  For deep well applications, it is necessary to use a tapered
                                                                 suckerrodstringstoreducethePRLatthesurface.Thelarger
                                                                 diameter rod is placed at the top of the rod string, then the
                       12.4.4 Peak Torque and Speed Limit        next largest, and then the least largest. Usually these are in
                       The peak torque exerted is usually calculated on the most  sequences up to four different rod sizes. The tapered rod
                       severe possible assumption, which is that the peak load  strings are designated by 1/8-in. (in diameter) increments.
                       (polished rod less counterbalance) occurs when the ef-  Taperedrodstringscanbeidentifiedbytheirnumberssuchas
                       fective crank length is also a maximum (when the crank
                                                                                   8
                       arm is horizontal). Thus, peak torque T is (Fig. 12.5)  a. No. 88 is a nontapered ⁄ 8 - or 1-in. diameter rod string
                                                                                         7
                                                                 b. No. 76 is a tapered string with ⁄ 8 -in. diameter rod at
                                        d 2
                                                                              6
                       T ¼ cC   (0:9   F 2 )W r Š  :      (12:28)  the top, then a ⁄ 8 -in. diameter rod at the bottom.
                           ½
                                        d 1
                                                                 c. No. 75 is a three-way tapered string consisting of
                       Substituting Eq. (12.25) into Eq. (12.28) gives  7 ⁄ 8 -in. diameter rod at top
                                                                   6
                           1                                        ⁄ 8 -in. diameter rod at middle
                       T ¼ SC   (0:9   F 2 )W r Š         (12:29)  5 ⁄ 8 -in. diameter rod at bottom
                             ½
                           2
                                                                 d. No. 107 is a four-way tapered string consisting of
                       or                                          10 ⁄ 8 -in. (or 1 ⁄ 4 -in.) diameter rod at top
                                                                            1

                                                                          1
                                                                                            10
                                   1  1     1                      9 ⁄ 8 -in. (or 1 ⁄ 8 -in.) diameter rod below ⁄ 8 -in. diameter rod
                                T ¼ S  W f þ (F 1 þ F 2 )W r       8 ⁄ 8 -in. (or 1-in.) diameter rod below ⁄ 8 -in. diameter rod
                                                                                           9
                                   2  2     2
                                                                   7                  8
                                                                    ⁄ 8 -in. diameter rod below ⁄ 8 -in. diameter rod
   168   169   170   171   172   173   174   175   176   177   178