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127
                                                              Analog Lowpass Filters








                       Source
                                    --              --             --               R L=50
                                                                   --
                                                    --
                                    --
                                       C 1 =492pF
                                                       C3=1.5915nF
                                                                      C5=492pF






                 Formulae for  Passive Lowpass Filter Denormalization


                       I have described the process of  passive filter denormalization. Now  its time to
                       write these as simple mathematical expressions:




                                  C*
                             C=--
                                2z& R
                       L*  and C* are the normalized lowpass component values. L and Care the tinal
                       values after scaling. In practice, the design would be scaled for impedance and
                       frequency in one step, by substitution of values into the given formulae.

                       A  simple example will  now  be given. Suppose a fourth-order lowpass filter is
                       required that has 600R load impedance and a cutoff frequency of  3.4kHz for
                       telephone band speech. The filter is to be driven from a OR source (Le.. an ideal
                       op-amp) and a 0.1 dB ripple Chebyshev response has been chosen.

                       The normalized values (refer to Chapter 2) are: L.1’  = 1.51567; C2‘ = 1.77396:
                       L3’  =  1.45978; C4‘  = 0.67474. The  L’  and  C’  here  refer  to  the  normalized
                       component  values  given  in  the  table.  The  apostrophe  indicates  that  the
                       ladder network begins with a series inductor. If the source had been of  infinite
                       impedance the ladder network would have begun with a capacitor and the values
                       would have been for C1,  L2. C3, and L4 respectively.

                       In the scaling formulae:
                                RL *          C*
                             L=-     and C=-
                                2z&          2Z&  R
                       R  = 600.  2z& = 2 1.363 radls.
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